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3 years ago

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Why is reactivity not a physical property

1 answer:

lbvjy [14]3 years ago

3 0

Reactivity is not a physical property because it's a characteristic of a chemical element or compound and is involved in chemical process.

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Calculate the pH of a solution with [H₃O⁺] = 1 × 10¯⁴ M to the correct number of decimal places.

wolverine [178]

I’m not sure 62840462

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3 years ago

The internal energy of a system __________. Question 66 options: is the sum of the kinetic energy of all of its components is th

9966 [12]

Answer:

The internal energy of a system <u>is the sum of the potential and kinetic energies of the components</u>

Explanation:

Internal energy is defined as the sum of two types of energy: kinetic energy and potential energy.

Kinetic energy is defined as the sum of all the kinetic energies that each element has within a system with respect to its center of mass. It is caused by the movement of particles. Meanwhile, the potential energy is the energy that is associated with each of the interactions. Potential energy is associated with the constituents of matter, of the electrostatic energy of each atom that is inside the molecules.

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3 years ago

What is the name of The compound?

Liono4ka [1.6K]

Answer:

But-2-ene is your answer i guess

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3 years ago

What is the molarity of a solution that contains 87.75g of NaCI in 500.ml of solution

Brut [27]

Answer:

M = 3.0 mol/L.

Explanation:

We can calculate the molarity of a solution using the relation:

<em>M = (mass x 1000) / (molar mass x V)</em>

M is the molarity "number of moles of solute per 1.0 L of the solution.

mass is the mass of the solute (g) (m = 87.75 g of NaCl).

molar mass of NaCl = 58.44 g/mol.

V is the volume of the solution (ml) (V = 500.0 ml).

∴ M = (mass x 1000) / (molar mass x V) = (87.75 g x 1000) / (58.44 g/mol x 500.0 ml) = 3.0 mol/L.

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3 years ago

A volume of 100 mL of 1.00 M HCl solution is titrated with 1.00 M NaOH solution. You added the following quantities of 1.00 M Na

s344n2d4d5 [400]

Answer:

a: before equivalence point

b: equivalence point

c: before equivalence point

d: after the eqivalence point

e: before equivalence point

f: after the eqivalence point

Explanation:

Balanced equation of reaction:

NaOH +HCl =NaCl +H2O;

Volume of HCl is fixed and it 100ml and concentration is 1.0M

N1 and N2 normality of HCl and NaOH respectively;

V1 and V2 volume of HCl and NaOH respectively;

we have given molarity but we need normality;

$Normality=molarity \times n-factor$

<em>but in case of NaOH and HCl n-factor is 1 for each.</em>

hence

normality=molarity;

At equivalence point: $N_1V_1=N_2V_2$

Before equivalence point : $N_1V_1>N_2V_2$

After the equivalence point: $N_1V_1$

$N_1V_1=100\times1=100$

case a: 5.00 mL of 1.00 M NaOH

$N_2V_2=5\times1=5$

$N_1V_1>N_2V_2$ hence it is before equivalence point

case b: 100mL of 1.00 M NaOH

$N_2V_2=100\times1=100$

$N_1V_1=N_2V_2$ hence it is equivalence point

case c: 10.0 mL of 1.00 M NaOH

$N_2V_2=10\times1=10$

$N_1V_1>N_2V_2$ hence it is before equivalence point

case d: 150 mL of 1.00 M NaOH

$N_2V_2=150\times1=150$

$N_1V_1$ hence it is after the eqivalence point

case e: 50.0 mL of 1.00 M NaOH

$N_2V_2=50\times1=50$

$N_1V_1>N_2V_2$ hence it is before equivalence point

case f: 200 mL of 1.00 M NaOH

$N_2V_2=200\times1=200$

$N_1V_1$ hence it is after the eqivalence point

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3 years ago