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3 years ago

[O.01]Which of these is the location where sea floor spreading occurs? abyss guyot ocean trenches mid-ocean ridges

Chemistry

1 answer:

Alika [10]3 years ago

6 0

Answer:

Sea floor spreading occurs in mid-ocean ridges

Explanation:

mid-ocean ridge: A location where sea floor spreading occurs. The release of magma at these active volcanic sites forms new rocks and rows of mountains.

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Helium gas diffuses 4 times as fast as an unknown gas. What is relative molecular mass of the gas

Inessa05 [86]

The relative molecular mass of the gas : 64 g/mol

<h3>Further explanation</h3>

Given

Helium rate = 4x an unknown gas

Required

The relative molecular mass of the gas

Solution

Graham's Law

$\tt \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }$

r₁=4 x r₂

r₁ = Helium rate

r₂ = unknown gas rate

M₁= relative molecular mass of Helium = 4 g/mol

M₂ = relative molecular mass of the gas

Input the value :

$\tt \dfrac{4r_2}{r_2}=\sqrt{\dfrac{M_2}{4} }\\\\16=\dfrac{M_2}{4}\\\\M_2=64~g/mol$

7 0

2 years ago

Consider the chemical reaction represented below. CH4 + 2O2 CO2 + 2H2O + Heat Which of the following statements about this react

dsp73

A. the reaction releases heat

6 0

3 years ago

Read 2 more answers

Choose the substance with the highest surface tension.

umka2103 [35]

Answer:

Hello

you're answer should be E.HOCH2CH2OH

hope this answer is correct

8 0

3 years ago

Determine the concentration of hydronium and hydroxide ions in a solution that has a pH of 1.6.

Veronika [31]

Answer:

The answer to your question is [H₃O⁺] = 0.025 [OH⁻] = 3.98 x 10⁻¹³

Explanation:

Data

[H⁺] = ?

[OH⁻] = ?

pH = 1.6

Process

Use the pH formula to calculate the [H₃O⁺], then calculate the pOH and with this value, calculate the [OH⁻].

pH formula

pH = -log[H₃O⁺]

-Substitution

1.6 = -log[H₃O⁺]

-Simplification

[H₃O⁺] = antilog (-1,6)

-Result

[H₃O⁺] = 0.025

-Calculate the pOH

pOH = 14 - pH

-Substitution

pOH = 14 - 1.6

-Result

pOH = 12.4

-Calculate the [OH⁻]

12.4 = -log[OH⁻]

-Simplification

[OH⁻] = antilog(-12.4)

-Result

[OH⁻] = 3.98 x 10⁻¹³

5 0

3 years ago

How many grams of SnO2 are required to produce 1.20x10^21 molecules of water?

Drupady [299]

Answer:

<u>0.150 grams</u>

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Explanation:

The balanced chemical reaction to obtain water from SnO₂ is:

SnO₂ + 2H₂ → Sn + 2H₂O

The mole ratio is:

$\dfrac{1molSnO_2}{2molH_2O}$

Find the number of moles equivalent to 1.20× 10²¹ molecules of water, using Avogadro's number:

$1.20\times 10^{21}molecules\times \dfrac{1mol}{6.022\times 10^{23}molecules}=1.9927\times 10^{-3}moles$

From the mole ratio, the number of moles of SnO₂ are half the number of moles of water. That is:

0.0019927 moles / 2 = 0.00099635 moles of SnO₂

Use the molar mass of SnO₂ to convert the number of moles to grams:

molar mass of SnO₂ = 150.71g/mol

mass of SnO₂ = 0.00099635mol × 150.71 g/mol = 0.150 grams.

The answer must be reported with 3 significant figures.

8 0

3 years ago