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3 years ago

What element would have this electron configuration: 1s22s22p 3s 3p 4s 3d

Chemistry

1 answer:

kirill [66]3 years ago

3 0

Answer: its either argon or phosphorus is this a constructed response or a multiple choice

Explanation:

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DNA replication takes place

I am Lyosha [343]

Answer:

DNA replication takes place in the chromosome which is located in the nucleus of a cell.

Explanation:

8 0

3 years ago

Conversion factor 2.23 seconds to kilograms

Archy [21]

there is no conversion between the two due to one is time and one is weight

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3 years ago

What is the difference between the number of electrons in an atom of selenium?

azamat

Explanation:

Supposing we have to find the difference between the number of electrons in Selenium and Aluminium.

Well, electrons can be transformed to an atomic number, so if SE is 34, that means it has 34 electrons. AI has an atomic number of 13, which means it has 13 electrons. So the difference is that more electrons than AI are available from SE.

3 0

3 years ago

Need help !!!!! ASAP

Julli [10]

<h2>Hello!</h2>

The answer is:

The new volume will be 1 L.

$V_{2}=1L$

To solve the problem, since we are given the volume and the first and the second pressure, to calculate the new volume, we need to assume that the temperature is constant.

To solve this problem, we need to use Boyle's Law. Boyle's Law establishes when the temperature is kept constant, the pressure and the volume will be proportional.

Boyle's Law equation is:

$P_{1}V_{1}=P_{2}V_{2}$

So, we are given the information:

$V_{1}=2L\\P_{1}=50kPa\\P_{2}=100kPa$

Then, isolating the new volume and substituting into the equation, we have:

$P_{1}V_{1}=P_{2}V_{2}$

$V_{2}=\frac{P_{1}V_{1}}{P_{2}}$

$V_{2}=\frac{50kPa*2L}{100kPa}=1L$

Hence, the new volume will be 1 L.

$V_{2}=1L$

Have a nice day!

4 0

3 years ago

What is the ionic equation of Aqueous calcium bromide was mixed with aqueous gold(I) perchlorate, and a crystallized gold(I) bro

Bumek [7]

Answer:- $2AuClO_4(aq) + CaBr_2(aq)\rightarrow 2AuBr(s)+ Ca(ClO_4)_2(aq)$

Explanations:- It's a double replacement reaction where a precipitate of silver(I)bromide is formed. A dpuble replacement reaction in general looks as AB + CD \rightarrow AD + CB

To balance the equation we need to multiply gold compounds on both sides by 2 and the balanced equation is..

$2AuClO_4(aq) + CaBr_2(aq)\rightarrow 2AuBr(s)+ Ca(ClO_4)_2(aq)$

6 0

3 years ago