Answer : The final equilibrium temperature of the water and iron is, 537.12 K
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
![q_1=-q_2](https://tex.z-dn.net/?f=q_1%3D-q_2)
![m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)](https://tex.z-dn.net/?f=m_1%5Ctimes%20c_1%5Ctimes%20%28T_f-T_1%29%3D-m_2%5Ctimes%20c_2%5Ctimes%20%28T_f-T_2%29)
where,
= specific heat of iron = 560 J/(kg.K)
= specific heat of water = 4186 J/(kg.K)
= mass of iron = 825 g
= mass of water = 40 g
= final temperature of water and iron = ?
= initial temperature of iron = ![352^oC=273+352=625K](https://tex.z-dn.net/?f=352%5EoC%3D273%2B352%3D625K)
= initial temperature of water = ![20^oC=273+20=293K](https://tex.z-dn.net/?f=20%5EoC%3D273%2B20%3D293K)
Now put all the given values in the above formula, we get:
![(825\times 10^{-3}kg)\times 560J/(kg.K)\times (T_f-625K)=-(40\times 10^{-3}kg)\times 4186J/(kg.K)\times (T_f-293K)](https://tex.z-dn.net/?f=%28825%5Ctimes%2010%5E%7B-3%7Dkg%29%5Ctimes%20560J%2F%28kg.K%29%5Ctimes%20%28T_f-625K%29%3D-%2840%5Ctimes%2010%5E%7B-3%7Dkg%29%5Ctimes%204186J%2F%28kg.K%29%5Ctimes%20%28T_f-293K%29)
![T_f=537.12K](https://tex.z-dn.net/?f=T_f%3D537.12K)
Therefore, the final equilibrium temperature of the water and iron is, 537.12 K
Answer:
What are the characteristics of a revolver?
Explanation:
The revolver features several firing chambers located within a revolving cylinder. The cylinder rotates as the revolver is fired, lining up each bullet mechanically.
Answer is: It has a negative charge and is located in orbitals around the nucleus.
The electron (symbol: e⁻) is a subatomic particle whose electric charge is negative one elementary charge.
Electrons are moving in energy levels around nucleus.
The electron has a mass that is approximately 1/1836 that of the proton.
Electrons have properties of both particles and waves.
I think the number of protons in the nucleus the number of valence electrons atomic mass...