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Nezavi [6.7K]
1 year ago
6

Arrange the procedural steps, from start to finish, that are required to prepare indigo from nitrobenzaldehyde and acetone in ba

se, and then test its ability as a dye.
Chemistry
1 answer:
lions [1.4K]1 year ago
5 0

Acetone has α-hydrogens (on both sides) and thus can be deprotonated to give a nucleophilic enolate anion. The aldehyde carbonyl is much more electrophilic than that of a ketone, and therefore reacts rapidly with the enolate.

<h3>What is nitrobenzaldehyde?</h3>
  • Synthesis. The synthesis of 3-nitrobenzaldehyde is achieved via nitration of benzaldehyde, which yields especially the meta-isomer. Creation allocation is about 19% for the ortho-, 72% for the meta- and 9% for the para isomers.
  • Acetone, propanone, or dimethyl ketone, is an organic combination with the formula (CH3)2CO. It is the easiest and smallest ketone. It is a colorless, highly volatile, and combustible liquid with a characteristic aromatic odor.
  • Nitration of benzene with conc nitric acid and conc sulphuric acid gives nitrobenzene. Chlorination with chlorine in the existence of anhydrous aluminum chloride gives meta nitro chlorobenzene.

To learn more about sulphuric acid, refer to:

brainly.com/question/4018599

#SPJ4

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Identify structure(s) for all constitutional isomers with the molecular formula C4H8 that have one double bond. Select all that
Alchen [17]

Answer:

a) But-1-ene

b) E-But-2-ene

c) Z-But-2-ene

d) 2-Methylpropene

Explanation:

In this case, if we want to draw the <u>isomers</u>, we have to check the<u> formula </u>C_4_H8 in this formula we can start with a linear structure with 4 carbons. We also know that we have a double bond, so we can put this double bond between carbons 1 and 2 and we will obtain <u>But-1-ene.</u>

<u />

For the next isomer, we can move the double bond to carbons 2 and 3. When we do this can have two structures. When the methyl groups are placed on the same side we will obtain <u>Z-But-2-ene</u>. When the methyls groups are placed on opposite sides we will obtain <u>E-But-2-ene.</u>

<u />

Finally, we can use a linear structure of three carbons with a methyl group in the middle with a double bond, and we will obtain <u>2-Methylpropene.</u>

<u />

See figure 1 to further explanations.

I hope it helps!

<u />

<u />

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