Answer:
Light blue colored precipitate of copper hydroxide, [Cu(OH)₂(H₂O)₄]
Explanation:
In an aqueous solution, copper (II) exists as hexaaquacopper(II) ion, having the molecular formula [Cu(H₂O)₆]²⁺.
When ammonia (NH₃) is reacted with hexaaquacopper(II) ion, [Cu(H₂O)₆]²⁺, a <u>light blue colored precipitate of </u><u>copper hydroxide</u>, [Cu(OH)₂(H₂O)₄] is formed, which is soluble in excess ammonia.
Reaction: [Cu(H₂O)₆]²⁺ (aq) + 2NH₃(aq) → [Cu(OH)₂(H₂O)₄](s) (↓) + 2NH₄⁺(aq)