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3 years ago

What initially forms as pale blue and pale green precipitate when nh3 is added to cuh2o6?

2 answers:

7 0

The chemical equation that shows the reaction between nh3 and cuh206 is detailed as: [Cu(H2O)6]2+ (aq) + 2NH3(aq). —> [Cu(OH)2(H2O)4](s) + 2NH4 + (aq). the blue precipitate is Cu(OH)2(H2O)4 in which the blue color is caused by the Cu present in the solid.

GenaCL600 [577]3 years ago

5 0

Answer:

Light blue colored precipitate of copper hydroxide, [Cu(OH)₂(H₂O)₄]

Explanation:

In an aqueous solution, copper (II) exists as hexaaquacopper(II) ion, having the molecular formula [Cu(H₂O)₆]²⁺.

When ammonia (NH₃) is reacted with hexaaquacopper(II) ion, [Cu(H₂O)₆]²⁺, a <u>light blue colored precipitate of </u><u>copper hydroxide</u>, [Cu(OH)₂(H₂O)₄] is formed, which is soluble in excess ammonia.

Reaction: [Cu(H₂O)₆]²⁺ (aq) + 2NH₃(aq) → [Cu(OH)₂(H₂O)₄](s) (↓) + 2NH₄⁺(aq)

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Answer: Ionic formula will be $Mg_3P_2$ .

Explanation: $Mg^{2+}$ and $P^{3-}$ ions will form a ionic compound. Ionic compounds have both metals and non-metals.

Here $Mg^{2+}$ is a metal and $P^{3-}$ is a non-metal.

The net charge on any compound must be 0.

So we need 2 phosphate ions to balance the charge on $Mg^{2+}$ ions. Similarly we need 3 Magnesium ions to balance the charge on $P^{3-}$ ions.

Criss-crossing the charges, we will get the formula as $Mg_3P_2$

Criss-crossing is shown in the image below.

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2 years ago

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