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Keith_Richards [23]
3 years ago
5

What initially forms as pale blue and pale green precipitate when nh3 is added to cuh2o6?

Chemistry
2 answers:
andre [41]3 years ago
7 0
The chemical equation that shows the reaction between nh3 and cuh206 is detailed as: [Cu(H2O)6]2+ (aq) + 2NH3(aq). —> [Cu(OH)2(H2O)4](s) + 2NH4 + (aq). the blue precipitate is Cu(OH)2(H2O)4 in which the blue color is caused by the Cu present in the solid.
GenaCL600 [577]3 years ago
5 0

Answer:

Light blue colored precipitate of copper hydroxide, [Cu(OH)₂(H₂O)₄]

Explanation:

In an aqueous solution, copper (II) exists as hexaaquacopper(II) ion, having the molecular formula [Cu(H₂O)₆]²⁺.

When ammonia (NH₃) is reacted with hexaaquacopper(II) ion, [Cu(H₂O)₆]²⁺, a <u>light blue colored precipitate of </u><u>copper hydroxide</u>, [Cu(OH)₂(H₂O)₄] is formed, which is soluble in excess ammonia.

Reaction: [Cu(H₂O)₆]²⁺ (aq) + 2NH₃(aq) → [Cu(OH)₂(H₂O)₄](s) (↓) + 2NH₄⁺(aq)

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Please help me!!!!
miv72 [106K]

Answer:

0.8g/ml

Explanation:

d=m/v

d=20/25

d=0.8

7 0
3 years ago
For the reaction N2(g) + 3H2(g) 2NH3(g), what will happen if hydrogen gas was removed from the reaction mixture? There will be a
Hoochie [10]
This uses something called <span>Le Chatelier's principle. It states essentially that any stress put upon a system will be corrected.

In more simple terms, it means that in an equilibrium, such as the equation N2(g) + 3H2(g) <=> 2NH3(g), removing a reactant will cause the system to create more of said reactant to compensate for its loss, or adding excess reactant will cause the system to remove some of the added reactant. For future reference, the same principle applies to products in an equilibrium as well. 

In this case, hydrogen gas is a reactant, and hydrogen is being removed. According to </span><span>Le Chatelier's principle, the system will shift to create more hydrogen gas. In essence, it will shift in the direction of the hydrogen gas, so there will be a shift toward the reactants.

To clear something up, Keq will not change, as it is a constant value with constant conditions (such as temperature, pressure, etc.).</span>
7 0
3 years ago
Decreasing the temperature of a reaction decreases the reaction rate because
Elza [17]
The answer u are looking for is b
4 0
3 years ago
Read 2 more answers
At a certain temperature this reaction follows second-order kinetics with a rate constant of 14.1·M−1s−1 : →2SO3g+2SO2gO2g Suppo
RoseWind [281]

Answer:

[SO_3]=0.25M

Explanation:

Hello there!

In this case, since the integrated rate law for a second-order reaction is:

[SO_3]=\frac{[SO_3]_0}{1+kt[SO_3]_0}

Thus, we plug in the initial concentration, rate constant and elapsed time to obtain:

[SO_3]=\frac{1.44M}{1+14.1M^{-1}s^{-1}*0.240s*1.44M}\\\\

[SO_3]=0.25M

Best regards!

4 0
2 years ago
Example of false solutions and true solutions <br>​
Kamila [148]

Answer:

answer in expl.

Explanation:

example of false solution.- Earth is not square

true eg. - we live in earth

3 0
3 years ago
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