All categories

4 years ago

What initially forms as pale blue and pale green precipitate when nh3 is added to cuh2o6?

2 answers:

7 0

The chemical equation that shows the reaction between nh3 and cuh206 is detailed as: [Cu(H2O)6]2+ (aq) + 2NH3(aq). —> [Cu(OH)2(H2O)4](s) + 2NH4 + (aq). the blue precipitate is Cu(OH)2(H2O)4 in which the blue color is caused by the Cu present in the solid.

GenaCL600 [577]4 years ago

5 0

Answer:

Light blue colored precipitate of copper hydroxide, [Cu(OH)₂(H₂O)₄]

Explanation:

In an aqueous solution, copper (II) exists as hexaaquacopper(II) ion, having the molecular formula [Cu(H₂O)₆]²⁺.

When ammonia (NH₃) is reacted with hexaaquacopper(II) ion, [Cu(H₂O)₆]²⁺, a light blue colored precipitate of copper hydroxide, [Cu(OH)₂(H₂O)₄] is formed, which is soluble in excess ammonia.

Reaction: [Cu(H₂O)₆]²⁺ (aq) + 2NH₃(aq) → [Cu(OH)₂(H₂O)₄](s) (↓) + 2NH₄⁺(aq)

You might be interested in

Find the standard enthalpy of formation of ethylene, C2H4(g), given the following data: C2H4(g) + 3 O2(g) --> 2CO2(g) + 2 H2O

Brums [2.3K]

Answer : The standard enthalpy of formation of ethylene is, 52.4 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The formation reaction of $C_2H_4$ will be,

$2C(s)+2H_2(g)\rightarrow C_2H_4(g)$ $\Delta H_{formation}=?$

The intermediate balanced chemical reaction will be,

(1) $C_2H_4(g)+3O_2(g)\rightarrow 2CO_2(g)+2H_2O(l)$ $\Delta H_1=-1411kJ$

(2) $C(s)+O_2(g)\rightarrow CO_2(g)$ $\Delta H_2=-393.5kJ$

(3) $H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l)$ $\Delta H_3=-285.8kJ$

Now we will reverse the reaction 1, multiply reaction 2 and 3 by 2 then adding all the equation, we get :

(1) $2CO_2(g)+2H_2O(l)\rightarrow C_2H_4(g)+3O_2(g)$ $\Delta H_1=+1411kJ$

(2) $2C(s)+2O_2(g)\rightarrow 2CO_2(g)$ $\Delta H_2=2\times (-393.5kJ)=-787kJ$

(3) $2H_2(g)+2O_2(g)\rightarrow 2H_2O(l)$ $\Delta H_3=2\times (-285.8kJ)=-571.6kJ$

The expression for enthalpy of formation of $C_2H_4$ will be,

$\Delta H_{formation}=\Delta H_1+\Delta H_2+\Delta H_3$

$\Delta H=(+1411kJ)+(-787kJ)+(-571.6kJ)$

$\Delta H=52.4kJ$

Therefore, the standard enthalpy of formation of ethylene is, 52.4 kJ

7 0

3 years ago

What are the purposes of a chemical equation? Check all that apply.

hjlf

The answer is the first one

5 0

4 years ago

Read 2 more answers

Red aesthetic and one other thing

Katena32 [7]

I was on the phone to see if you wanted me a couple questions and I would be able answer questions on how

5 0

3 years ago

Read 2 more answers

2) 183 cg = kg 5 .00183 kg 0.0183 kg .183 kg 3) 0.25 kg = g

OlgaM077 [116]

Answer:

183 cg = 0.00183 kg

0.25 kg = 250 g

Explanation:

Use conversion factors. 1kg is equal to 1 x 10^5 cg (100000) and 1 kg is equal to 1 x 10^3 grams (1000 grams).

5 0

4 years ago

When we write the formula for an ionic compound, we are merely indicate the "molecules" in the compound with that formula. expla

belka [17]

When writing an ionic compound formula, a "molecular" form is used. The formula is made with allowance for ion charges.
For example,
Ca²⁺ and NO₃⁻ ⇒ Ca(NO₃)₂
Al³⁺ and SO₄²⁻ ⇒ Al₂(SO₄)₃

3 0

4 years ago