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3 years ago

Distinguish between constructive interference and destructive interference.

Physics

1 answer:

TEA [102]3 years ago

5 0

construction interference is when you build things up and destructive interference is when you tear things down

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A 1.7 kg book is lying on a 0.77 m -high table. You pick it up and place it on a bookshelf 2.0 m above the floor. how much work

luda_lava [24]

You are given the mass of the book with an initial height of 0.77m. You are also given the final height of the book, 2m above the floor. The problem requires you to find the work done on the book. It is said that work is equal to force times distance. And that force is equal to mass times acceleration due to gravity.
W=Fd
W=mgd=mgh
W=(1.7kg)(9.8m/s^2)(2m-0.77m)
W=20.49J
<span>The work is equal to 20.49J.</span>

4 0

3 years ago

A remote controlled toy car starts from rest and begins to accelerate in a straight line. The figure below represents "snapshots

Nikolay [14]

(a). The car's average velocity between t = 1.0s to t = 1.5s will be - $1\;m/s$

(b). The car's acceleration at t = 1.5s will be - $0.4\;m/s^{2}$

(c). Car's speed is increasing with time.

We have a a remote controlled toy car that starts from rest and begins to accelerate in a straight line.

We have to determine -

The car's average velocity (in m/s) in the interval between -

t = 1.0 s to t = 1.5 s.

The car's acceleration at t = 1.5 s.
Determining whether car's speed increasing or decreasing with time.

<h3>What is Acceleration?</h3>

The rate of change of velocity with respect to time is called Acceleration. Mathematically -

$$a=\frac{dv}{dt}$

According to the question, we have the following data for the Car -

t = 0s → x = 0m

t = 0.5s → x = 0.1m

t = 1.0s → x = 0.4m

t = 1.5s → x = 0.9m

t = 2.0s → x = 1.6m

PART - A

The car's average velocity between t = 1.0s to t = 1.5s will be -

$$v_{avg} = \frac{0.9-0.4}{1.5-1}= 1 m/s$

PART - B

Velocity at t = 1.5 s will be -

$$v(1.5)=\frac{0.9}{1.5}= 0.6\;m/s$

The car's acceleration at t = 1.5s will be -

$$a(1.5) = \frac{v}{t} = \frac{0.6}{1.5} = 0.4\;m/s^{2}$

PART - C

Since, the acceleration of the car is positive, this means that the car is accelerating in the forward direction. Hence, its speed is increasing with time.

[ The following data was missing in your answer. The complete question would include this data also -

t = 0s → x = 0m

t = 0.5s → x = 0.1m

t = 1.0s → x = 0.4m

t = 1.5s → x = 0.9m

t = 2.0s → x = 1.6m ]

To solve more questions on Kinematics, visit the link below-

brainly.com/question/17272824

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7 0

1 year ago

Read 2 more answers