The period of a simple pendulum is given by:

where L is the length of the pendulum and g is the gravitational acceleration.
The pendulum in our problem makes one complete vibration in 0.333 s, so its period is T=0.333 s. Using this information, we can re-arrange the previous formula to find the length of the pendulum, L:
Take a look at the attachment below. As you can see, the figure demonstrates a 90 degree angle such that the surfaces are perpendicular, and hence are independent of the angle of incidence. You could say that this forms a part of a parallelogram -
Force=7N-5N
=2N
It is because of difference between direction
More mass is the correct answer.
Using first equation of motion;
vf = vi + at --------------------- (1)
where vf = final velocity
vi = initial velocity
a = acceleration (here it is considered to be gravitational acceleration)
t = time
As
vi = 1.8 m/s
vf = 0 m/s
a = g = -9.8 m/s^2 (negative sign is due to the upward motion of tina)
using equation (1),
0 = 1.8 + (-9.8 * t)
t = 9.8/1.8
t = 0.1836 seconds
but the tina has to travel back to the ground, hence the time taken by tina to be in the air will be
t = 2 * 0.1836
t = 0.367 seconds