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2 years ago

What is the ratio of the number of bats to the total number of animals?

Mathematics

1 answer:

LenKa [72]2 years ago

4 0

Answer:1:6

Step-by-step explanation:

There are 6 animals total, and only 1 bat. So the ratio of bats to the total amount of animals is 1:6

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The volume V of a cube with sides of length x inches is changing with respect to time t (in seconds). When the sides of the cube

goldfiish [28.3K]

Answer:

dV/dt = 3×10^2 × 0.5 = 150 in^3/sec

the volume of the cube is increasing at 150in^3/sec

Step-by-step explanation:

Volume V = length l^3

V = x^3

Differentiating both sides;

dV/dt = 3x^2 dv/dt

Given;

x = 10 in

dx/dt = 0.5 in/sec

dV/dt = 3×10^2 × 0.5 = 150 in^3/sec

the volume of the cube is increasing at 150in^3/sec

5 0

3 years ago

How do you get 189 as the answer? Please help

OLga [1]

I don't understand what one

4 0

3 years ago

For any number n>1, is

Simora [160]

The right answer is A ! :)

7 0

2 years ago

Your Nana gives you $50 for making all A’s/B’s on your last report card. You have been eying a new pair of Crocs + their fancy c

satela [25.4K]

Answer:

Yes you have enough money because with the dicound the crocs are $45.50

Step-by-step explanation:

u have $50 the crocs is $65 but have 30% off

$65 with 30% off is $45.50

7 0

2 years ago

Read 2 more answers

A motorboat takes 5 hours to travel 100mi going upstream. The return trip takes 2 hours going downstream. What is the rate of th

Temka [501]

The boat went 5hours upstream, let's say it has a "still water" speed rate of "b", it went 100miles... however, going upstream is going against the current, let's say the current has a speed rate of "c"

so, when the boat was going up, it wasn't really going "b" fast, it was going " b - c " fast, because the current was eroding speed from it

now, when coming down, the return trip, well the length is the same, so the distance is also 100miles, it only took 2hrs though, because, the boat wasn't coming down "b" fast, it was coming down " b + c " fast, because the current was adding speed to it, so it came down quicker

now, recall your d = rt, distance = rate * time

$\bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
upstream&100&b-c&5\\
downstream&100&b+c&2
\end{array}
\\\\\\
\begin{cases}
100=(b-c)5\\
\qquad \frac{100}{5}=b-c\\
\qquad 20=b-c\\
\qquad 20+c=\boxed{b}\\
100=(b+c)2\\
\qquad 50=b+c\\
\qquad 50=\boxed{20+c}+c
\end{cases}$

solve for "c", to see what's the current's speed

what's "b"? well 20+c = b

4 0

2 years ago