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Anton [14]
3 years ago
10

7. The Voyager 1 space probe was launched in the 1970's and is now the furthest

Physics
1 answer:
NikAS [45]3 years ago
6 0

Answer:

v = 16.98 km/s

Explanation:

Given that,

Distance, d = 4500 km

Time, t = 265 s

We need to find its average speed. The total distance covered divided by total time taken is called average speed of an object. So,

v=\dfrac{4500\ km}{265\ s}\\\\=16.98\ km/s

So, the average speed is 16.98 km/s.

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The magnitude of the magnetic field B a distance r from a long straight wire is B = μ 0 I 2 π r where μ 0 is the permeability co
PSYCHO15rus [73]

Answer:

The magnetic field is lowest for largest distance and highest when distance is least.

Explanation:

The magnitude of magnetic field strength at a distance 'r' from a long straight wire carrying current 'I' is given as:

B=\frac{\mu_0 I}{2\pi r}\\Where,\mu_0\to permeability\ constant\ of\ free\ space

Now, as per question, the distance 'r' is varied while keeping the current constant in the wire.

As seen from the above formula, the magnitude of magnetic field strength for a constant current varies inversely with the distance 'r'. This means that, as the value of 'r' increases, the magnitude of magnetic field strength decreases and vice-versa.

Therefore, the magnitude of magnetic field strength is maximum when the distance 'r' is least and the magnetic field is minimum for the largest distance.

Example:

If B_1, B_2,\ and\ B_3 are the magnitudes of magnetic field strengths for distances r_1,r_2, \ and\ r_3 respectively such that r_1. Now, as per the explanation above, the order of magnitudes of magnetic field strength is:

B_1>B_2>B_3

6 0
4 years ago
Un carro parte del reposo y acelera uniformemente a 4.0 m / s^2 durante 5.0 s. A continuación, mantiene la velocidad que alcanzó
Arada [10]

Answer:

Average speed of the car = 16.53 m.s

Explanation:

For first 5 seconds:

As the car starts from rest, so the initial speed of the car, u=0

Acceleration, a= 4 m/s^2

So, the final speed (speed at time, t=5 second)

v=u+at

v=0 + 4 x 5 = 20 m/s

Distance covered,

s=ut+\frac 1 2 a t^2 \\\\s=0+\frac 1 2 \times 4 \times 5^2

s=50 m

As the car maintained the constant speed of 20 m/s for the next 10 seconds.

Distance traveled in 10 seconds, d=20 x 10 =200 m

For the last 4 seconds:

The car slows down at the rate of 2.0 m / s ^ 2 from the speed of 20 m/s.

As the car slows down, so the acceleration will be negative, i.e a=-2 m/s^2

s=ut+\frac 12 at^2 \\\\s=20\times 4 +\frac 12 (-2)4^2

s=80-16=64 m.

Considering all three cases, the total distance covered=

=50+200+64=314 m

Total time= 5+10+4=19 s

So, the averate peed= Totat distance covered / total time taken

=314/19=16.53 m/s

6 0
3 years ago
A rotating water pump works by taking water in at one side of a rotating wheel, and expelling it from the other side. If a pump
Xelga [282]

Answer:

Explanation:

initial angular velocity, ωo = 0 rad/s

angular acceleration, α = 30.5 rad/s²

time, t = 9 s

radius, r = 0.120 m

let the velocity is v after time 9 s.

Use first equation of motion for rotational motion

ω = ωo + αt

ω = 0 + 30.5 x 9

ω = 274.5 rad/s

v = rω

v = 0.120 x 274.5

v = 32.94 m/s

8 0
3 years ago
How do electromagnetic waves differ from mechanical waves?
stich3 [128]

They don't require a medium to propagate, meaning that they can travel through air, solid objects, and space.

6 0
4 years ago
In how many ways can five basketball players be placed in three postitions?
Mazyrski [523]

Answer:

Well if they playing a game like that

4 0
3 years ago
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