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3 years ago

7. The Voyager 1 space probe was launched in the 1970's and is now the furthest

Physics

1 answer:

NikAS [45]3 years ago

6 0

Answer:

v = 16.98 km/s

Explanation:

Given that,

Distance, d = 4500 km

Time, t = 265 s

We need to find its average speed. The total distance covered divided by total time taken is called average speed of an object. So,

$v=\dfrac{4500\ km}{265\ s}\\\\=16.98\ km/s$

So, the average speed is 16.98 km/s.

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Change a speed of 72.4 miles per hour to its equivalent in meters per second.

4vir4ik [10]

Answer:

Speed in meter/sec will be 32.1777 m /sec

Explanation:

We have given speed = 72.4 miles per hour

We have to convert this speed in meter per second

We know that 1 miles = 1.6 km

So 72.4 miles = 72.4×1.6= 115.84 km

We also know that 1 km = 1000 m

So 115.84 km $=115.84\times 10^3m$

We know that 1 hour = 60×60 = 3600 sec

So $72.4miles/hour=\frac{72.4\times 1600m}{3600sec}=32.1777m/sec$

7 0

4 years ago

Select the correct answer.<br> What was the main objective of the Discovery missions?

Nimfa-mama [501]

Answer:

Explanation:

exploration surrounding our universe will give us a better understanding of it.

6 0

3 years ago

Which of the following best defines amplitude?

ziro4ka [17]

The answer to that question is C

8 0

4 years ago

The area under acceleration time garph represents?

Keith_Richards [23]

Answer:

Change in Velocity because

$at = v$

Explanation:

Remeber area is length times Width. In this case, the area under a accleraton vs time graph is Accleration Times Time. Which is velocity

8 0

2 years ago

Read 2 more answers

An object is thrown directly up (positive direction) with a velocity (vo) of 20.0 m/s and do= 0. How high does it rise (v = 0 cm

Anit [1.1K]

Answer:

The value of d is 20.4 m.

(C) is correct option.

Explanation:

Given that,

Initial velocity = 20 m/s

Final velocity = 0

We need to calculate the time

Using equation of motion

$v = u+gt$

Where, u = Initial velocity

v = Final velocity

Put the value into the formula

$t = \dfrac{20}{9.8}$

$t= 2.04\ sec$

We need to calculate the distance

Using equation of motion

$s = ut+\dfrac{1}{2}gt^2$

$s=0+\dfrac{1}{2}\times9.8\times(2.04)^2$

$s=20.4\ m$

Hence, The value of d is 20.4 m.

4 0

3 years ago