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kirill115 [55]
3 years ago
14

what has more momentum, a baseball traveling at 4 m/s or a baseball traveling at 16m/s ? and which has more energy ?

Physics
1 answer:
Anna007 [38]3 years ago
3 0
We know the formulas for momentum and energy. But they both involve the mass of
the object, and we don't know the mass of the baseball.  What can we do ?

It's not a catastrophe.  The question only asks which one is bigger.  If we're clever,
we can answer that without ever knowing how much the momentum or the energy
actually is.  We know that both baseballs have the same mass, so let's just call it
' M ' and not worry about what it really is.

<u>Momentum of anything = (mass) x (speed)</u>
Momentum of the first baseball = (M) x (4 m/s) = 4M
Momentum of the second one = (M) x (16 m/s) = 16M
The second baseball has 4 times as much momentum as the first one has.

<u>Kinetic energy of anything = 1/2 (mass) x (speed squared)</u>
KE of the first baseball = 1/2 (M) x (4 squared) = 8M
KE of the second one = 1/2 (M) x (16 squared) = 128M
The second baseball has 16 times as much kinetic energy as the first one has.
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Hello,

Here is your answer:

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tankabanditka [31]

You must throw the snow ball by velocity 9.43 m/s horizontally to

hit him

Explanation:

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1. The initial velocity of the ball is v

2. The vertical component of v is zero because you throw the ball

     horizontally

3. The vertical distance h is 5.5 m

4. The horizontal distance x is 10 m

We need to find how fast you must throw the snow ball to hit him

→ h = v_{y} t + \frac{1}{2} g t²

→ h = -5.5 m ⇒ height below the point of thrown

→ g = -9.8 m/s²

→  v_{y} = 0 ⇒ vertical component of v

→ -5.5 = (0) t + \frac{1}{2} (-9.8) t²

→ - 5.5 = -4.9 t²

Divide both sides by -4.9

→ t² = 1.12245

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Divide both sides by 1.06

→ v = 9.43 m/s

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