Asteroids do this because of Newton's Third Law. When a asteroid hits something, it will keep on moving (spinning) until it hits something else.
The figure mentioned on the question is in the attachment.
Answer: a)
= - 38.35N
b)
= 30.5 N
c)
= 27.45 N
d) a = - 13.16 m/s²
Explanation: A block on an inclined plane has 3 forces acting on it:
- Force due to gravity
= m.g; - Normal Force due to the plane;
- Force of Friction
= µ.N;
Since the plane is inclined, Normal Force is equal the y-component of the force due to gravity and Force of friction and the x-component of the force due to gravity are opposite forces.
The second attachment ilustrate the forces acting on the block.
Calculating:
A) The magnitude of the x-component of Force due to gravity:
According to the second image:
= P.sinθ
= 5.9.8.sin(36.8)
= - 38.35 N
B)
=
= m.g.cosθ
= 5.9.8.cos(36.8)
= 30.5 N
C)
= 0.9.30.5
= 27.45 N
D) For the acceleration, use Newton's Law:
= m . a
If there is movement, it is only on x-axis, so the net force is:
-
= m.a
- 38.35 - 27.45 = 5a
a = - 13.16 m/s²
The value of acceleration shows there is <u>no</u> <u>movement</u> on the x-axis due to the friction.
Answer:
potential energy = mgh , where m is mass of body , g is acceleration due to gravity and h is given height
since both of the body are at same height above the ground , so the body having greater mass will have more potential energy
that is 20 kg body will have higher P.E
Explanation:
Answer:
the location of the center of gravity for the entire body is 1.08 m
Explanation:
Given the data in the question;
w1 = 458 N, y1 = 1.34 m
w2 = 120 N, y2 = 0.766 m
w3 = 89.8 N, y2 = 0.204 m
The location arrangement of the body part is vertical, locate the overall centre of gravity by simply replacing the horizontal position x by the vertical position y as measured relative to the floor.
so,
= (w1y1 + w2y2 + w3y3 ) / ( w1 + w2 + w3 )
so we substitute in our values
= (458×1.34 + 120×0.766 + 89.8×0.204 ) / ( 458 + 120 + 89.8 )
= 723.9592 / 667.8
= 1.08 m
Therefore, the location of the center of gravity for the entire body is 1.08 m
Gravitational force of attraction between two objects can be calculated from the following formula:

Where m with subscript stands for mass of the object and r is the distance between them.
When we double the mass of those two objects, distance between them stays the same, while in the numerator we have:

When numerator in the second case 4 times greater than the 'original' numerator and denominator stays the same, force becomes 4 times greater.