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2 years ago

Describe the relationship between force and mass when the acceleration of two objects remain constant

Physics

1 answer:

LekaFEV [45]2 years ago

6 0

Answer:

If they both remain constant they ain't moving, It states that the rate of change of velocity of an object is directly proportional to the force applied and takes place in the direction of the force. It is summarized by the equation

Explanation:

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A(n) 930 N crate is being pushed across a level floor by a force of 400 N at an angle of 20◦ above the horizontal. The coefficie

Nana76 [90]

Answer:

The magnitude of the acceleration of the box is $2.291\,\frac{m}{s^{2}}$ .

Explanation:

The free body diagram of the crate is included as attachment, whose equations of equilibrium are described below:

$\Sigma F_{x} = P\cdot \cos 20^{\circ} - \mu_{k}\cdot N = \left(\frac{W}{g}\right)\cdot a$

$\Sigma F_{y} = P\cdot \sin 20^{\circ} + N - W = 0$

From second equation of equilibrium we find an expression for the normal force and find the respective value:

$N = W - P \cdot \sin 20^{\circ}$

$N = 930\,N - 400\cdot \sin 20^{\circ}\,N$

$N = 793.192\,N$

Lastly, the acceleration experimented by the crate during pushing is cleared in the first equation of equilibrium and consequently calculated:

$a = \frac{P\cdot \cos 20^{\circ}-\mu_{k}\cdot N}{\frac{W}{g} }$

$a = \frac{400\cdot \cos 20^{\circ}\,N-0.20\cdot (793.192\,N)}{\frac{930\,N}{9.807\,\frac{m}{s^{2}} } }$

$a = 2.291\,\frac{m}{s^{2}}$

The magnitude of the acceleration of the box is $2.291\,\frac{m}{s^{2}}$ .

3 0

2 years ago

What is the actual land form of a shield volcano?<br><br> PLEASE HELP

Mazyrski [523]

The land form is formed by lava flows of low viscosity

Hope this helps! :)

4 0

3 years ago

Read 2 more answers

When placed near another charge, a 20 microcoulomb charge experiences an attractive force of 0.080 N. What is the electric field

prohojiy [21]

Answer:

E = 4000 N/C

Explanation:

Given the following data;

Force = 0.080 N.

Charge, q = 20 microcoulomb = 20 * 10^-6 = 2 * 10^-5 Coulombs

To find the electric field strength;

Mathematically, the electric field strength is given by the formula;

Electric field strength = force/charge

Substituting into the formula, we have;

E = 0.080/0.00002

E = 4000 N/C

8 0

3 years ago

The equation for the chemical reaction shown is not balanced. What number should replace the question mark to balance this equat

Fudgin [204]

The equation is balanced as it is.

7 0

3 years ago

If a device uses 280 watts of power a day, about how many kilowatt-hours will it use in 30 days?

Novay_Z [31]

Answer:C

Explanation:

Power=280watts=280/1000 kilowatts

Power=0.28 kilowatts

Device use 0.28 kilowatts in 1 day

1day=24hours

Device use 0.28 kilowatts in 24hours

30days=30 x 24=720 hours

For 720 hours=(0.28x720) ➗ 24

For 720 hours=201.6 ➗ 24

For 720 hours=8.4

6 0

2 years ago