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PolarNik [594]
3 years ago
14

which of these things could lead to type 2 diabetes? a) sexual activity b) smoking c) obesity d) taking drug

Physics
1 answer:
gavmur [86]3 years ago
8 0
The answer is C because Type 2 diabetes<span> usually begins with insulin resistance, a condition linked to excess weight in which your body's cells do not use insulin properly. As a result, your body needs more insulin to help glucose enter cells. The reason why your body needs more insulin is because it was reduced of it from obesity.</span>
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Conclusion for ohm law
kari74 [83]
Ohm’s Law states that electrical current is proportional to voltage and therefore inversely proportional to resistance - V = I x R
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3 years ago
If the body's temperature is above 105 °F for a prolonged period, heat stroke
seraphim [82]

Answer:

A

Explanation:

C = (F-32)*5/9 = 73*5/9 = 40.55555

since the answers are spread apart, technically you can just estimate by doing -32

and then /2

since 5/9 is close to 1/2

7 0
3 years ago
Wegut.
AVprozaik [17]

We/Wm = ge/gm = 120N/1.2N

or

gm = ge/100 = 0.1 m/s^2

density = mass/volume = 3M/(4pir^3)

Re-arranging this equation, we get

M/r^2 = (4/3)×pi×(density)×r

From Newton's universal law of gravitation, the acceleration due to gravity on the moon gm is

gm = G(M/r^2) = G×(4/3)×pi×(density)×r

Solving for density, we get the expression

density = 3gm/(4×pi×G×r)

= 3(0.1)/(4×3.14×6.67×10^-11×2.74×10^6)

= 130.6 kg/m^3

6 0
3 years ago
By what factor would your weight increase if you could stand on the sun? (never mind that you can't.)
Fofino [41]

Gravity on the surface of sun is given as

g = \frac{GM}{R^2}

here we know that

M = 1.98 \times 10^{30} kg

R = 6.95 \times 10^8 m

now we will have

g = \frac{(6.67 \times 10^{-11})(1.98 \times 10^30)}{(6.95 \times 10^8)^2}

g = 273.4 m/s^2

now we need to find the ratio of weight on surface of sun and on surface of Earth

R = \frac{mg_{sun}}{mg_{earth}}

R = \frac{273.4}{9.8} = 28 times

so weight will increase by 28 times

6 0
3 years ago
8. A sprinter on a school track team is running north at a velocity of 6.0 m/s. After 5.0 s, she
Marysya12 [62]

Answer:

acc. = 4-(-6) /5= 10/5=2 m/s^2

6 0
3 years ago
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