Heat<span> may be </span>transferred<span> by means of conduction, convection, or radiation. </span>
Answer:
(a) Magnitude of static friction force is 109 N
(b) Minimum possible value of static friction is 0.356
Solution:
As per the question;
Horizontal force exerted by the girl, F = 109 N
Mass of the crate, m = 31.2 kg
Now,
(a) To calculate the magnitude of static friction force:
Since, the crate is at rest, the forces on the crate are balanced and thus the horizontal force is equal to the frictional force, f:
F = f = 109 N
(b) The maximum possible force of friction between the floor and the crate is given by:
where
N = Normal reaction = mg
Thus
For the crate to remain at rest, The force exerted on the crate must be less than or equal to the maximum force of friction.
Answer:
Explanation:
The first derivative of the angular momentum with respect to time is defined as the magnitude of the average torque acting on the particle:
So, we calculate the magnitude of the average torque, dividing the change of the angular momemtum into the time:
Answer:
Explanation:
<u>Given:</u>
- x-component of acceleration of the cart,
- y-component of acceleration of the cart,
- x-component of initial velocity of the cart,
- y-component of initial velocity of the cart,
Let the x and y components of the final velocity of the cart when the cart reaches its greatest y coordinate be respectively.
When the cart reaches its greatest y-coordinate then the y component of its final velocity should be zero,
Let the cart reaches its greatest y-coordinate at time t, then using the following equation:
At this time, the x component of the velocity of the particle is given by
Thus, the velocity of the cart when it reaches its greatest y coordinate, in unit-vector notation, is given by
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Explanation: