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Romashka [77]
4 years ago
13

What physics is involved for a passenger feeling pushed backward into the seat of an airplane when it accelerates along the runw

ay during takeoff?
Physics
2 answers:
kifflom [539]4 years ago
8 0

Newton's laws of motion, #1 and #2, explain everything the passenger feels in that situation.

timofeeve [1]4 years ago
7 0

It's due to Inertia. The law of Inertia states that a body will try to retain its movement state if possible. This means, if a body is at rest, it will try to remain at rest using forces. Similarly, if it's in movement, it will try to remain in movement.

In this example, the plane is moving forwards, and so do the seats, which in turn push the passenger forwards.The force felt is Inertia acting on the body, trying to counter the movement.

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Can someone please help me with these 2 questions
jok3333 [9.3K]
1. Answer: 7.75 seconds
Explanation: 76-14=62 metres
62/8=7.75 seconds

2. Answer: 2.5 seconds
Explanation: 28-18=10 metres
10/4=2.5 seconds
5 0
4 years ago
A 2.40 kg can of coffee moving at 1.50 m/s in the +x-direction on a kitchen counter collides head-on with a 1.20 kg box of macar
liraira [26]

Answer:

The macaroni travels with a velocity of 1.35 m/s in the +x-direction.

Explanation:

By the conservation of momentum principle and assuming there is no external force (e.g. friction) acting on the system, the total initial momentum is equal to the total final momentum.

We take all velocities in the +x-direction as positive.

Initial momentum of coffee can = (2.40 kg)(1.50 m/s) = 3.60 kg m/s

Initial momentum of macaroni = (1.20 kg)(0.00 m/s) = 0.00 kg m/s

Total initial momentum = (3.60 + 0.00) kg m/s = 3.60 kg m/s

Final momentum of coffee can = (2.40 kg)(0.825 m/s) = 1.98 kg m/s

Final momentum of macaroni = (1.20 kg)(v m/s) = 1.20v kg m/s

Total final momentum = (1.98 + 1.20v) kg m/s

Equating both initial and final total momenta,

3.60 kg m/s = (1.98 + 1.20v) kg m/s

1.20v kg m/s = 1.62 kg m/s

v = (1.62 kg m/s) ÷ (1.20 kg) = 1.35 m/s

Since this is positive, the macaroni travels with a velocity of 1.35 m/s in the +x-direction.

6 0
3 years ago
Car's mass is 950kg. It's driven at 100km/h. How big is the kinetic energy?
polet [3.4K]

Answer:

4750000 J

Explanation:

Kinetic Energy= 1/2* mass* velocity²

1/2*950*100²=4750000

8 0
3 years ago
A vector in the xy plane has components -14.0 units in the x-direction and 30.0 units in the y-direction. What is the magnitude
OverLord2011 [107]

\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}

We would calculate the magnitude by applying pythagorean theorem:

\longrightarrow \sf{Magnitude= \sqrt{(-14)^2 } + 30^2}

\longrightarrow \sf{Magnitude = 33.12}

\longrightarrow \sf{The \:  vector \: is \: (- 14, 30)}

The angle between two vectors is given by the formula:

\sf{\longrightarrow \small  \cos \emptyset =  \dfrac{(a1b1 + a2b2)}{ \sqrt{(a1)^2 + (a2)^2√(b1)^2 + (b2)^2} } }

In two dimensional, the x axis of vector form is:

\small\sf{\longrightarrow (b1, b2) = (1, 0) }

\sf{\longrightarrow \small \cos \:  \emptyset =  \dfrac{(14 * 1 + 30 x 0)}{( \sqrt{(-14)^2 + (30)^2)(√(1)^2 + (0)^2)} } }

\small\longrightarrow \sf{ \dfrac{14}{33.12} }

\small\longrightarrow \sf{\emptyset  \:  = arcCos (\dfrac{ - 14}{33.12} )}

\small\longrightarrow \sf{\emptyset= 115^\circ}

\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}

\small\bm{The \: angle  \: between  \: the  \: vector \: }

\small\bm{and \: \: the \: \: positive \: \: x \: \: axis \: \: is \: \: \: 115^\circ .}

6 0
2 years ago
Can someone help with this question pls
morpeh [17]
I solved it and got 374.2N so i would put 375N

sorry i didn’t get any of the ones on there, i probably made a mistake.
6 0
3 years ago
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