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pishuonlain [190]
3 years ago
13

What is the freezing point (in c) of a 1.56 m aqueous solution of CaCl2? (Report amount to three decimal points)

Chemistry
1 answer:
djverab [1.8K]3 years ago
8 0
25.687 degrees celcius
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What noble gas configuration does oxygen achieve when bonded?
Greeley [361]

Answer:

1s2 2s2 2p6

Explanation:

ththe noble gas config. of neon

5 0
2 years ago
Calculate the standard potential for the following galvanic cell: Fe(s) | Fe2+(aq) || Ag+(aq) | Ag(s) which has the overall bala
Nataly [62]

Answer:

E° = 1.24 V

Explanation:

Let's consider the following galvanic cell: Fe(s) | Fe²⁺(aq) || Ag⁺(aq) | Ag(s)

According to this notation, Fe is in the anode (where oxidation occurs) and Ag is in the cathode (where reduction occurs). The corresponding half-reactions are:

Anode: Fe(s) ⇒ Fe²⁺(aq) + 2 e⁻

Cathode: Ag⁺(aq) + 1 e⁻ ⇒ Ag(s)

The standard cell potential (E°) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.

E° = E°red, cat - E°red, an

E° = 0.80 V - (-0.44 V) = 1.24 V

6 0
3 years ago
Which of the following is a property of carbon atoms?
marusya05 [52]

Answer:

B. They can for covalent bonds with other atoms.

Explanation:

Carbon = King of the elements on the periodic table

For its proclivity to form stable covalent bonds with multivalent atoms.

5 0
3 years ago
Read 2 more answers
How many electrons does the copper atom lose in the process: Cu → Cu3+ + ? electrons
alexdok [17]

Answer:

3

Explanation:

6 0
2 years ago
How much heat is needed warm 65.34 g of water from 18.43 to 21.75
BaLLatris [955]

Given that  

Mass of water = 65.34 g

Amount of heat = mass of water * specific heat (temperature change

)

= 65.34 g * 4.184 J / g-C ( 21.75-18.43 )C

= 907.63  J  

= 0.908 KJ

And  

1 cal = 4.186798 J

907.63 J * 1 cal / 4.186798 J =216.78  cal

Or0.218 kcal  


5 0
3 years ago
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