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nataly862011 [7]
3 years ago
15

Help would be appreciated please!

Chemistry
2 answers:
saveliy_v [14]3 years ago
7 0
I can’t help but just wanted to say love ur pfp
PolarNik [594]3 years ago
5 0
Highlight it and hit ctrl shift and l then scroll till u see your question and the answer should be there bc i've done it before and i have got a 100 each time
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Can someone balance these equations?
wolverine [178]

This is mind numbing, but I got you.

3NaOH + 1FeCl<em>3</em> = 1Fe(OH)<em>3 </em>+ 3NaCl

3Mg + 2H<em>3</em>(PO)<em>4</em> = 1Mg(PO<em>4</em>)<em>2</em> + 3H<em>2</em>

3 0
3 years ago
Consider the dissolution of calcium hydroxide:
Crazy boy [7]

Answer:

1. K_eq = [Ca^{2+][OH^-]^2 = K_{sp}

2. a. No effect;

b. Products;

c. Products;

d. Reactants

Explanation:

1. Equilibrium constant might be written using standard guidelines:

  • only aqueous species and gases are included in the equilibrium constant excluding solids and liquids;
  • the constant involves two parts: in the numerator of a fraction we include the product of the concentrations of products;
  • the denominator includes the product of the concentrations of reactants;
  • the concentrations are raised to the power of the coefficients in the balanced chemical equation.

Based on the guidelines, we have two ions on the product side, a solid on the left side. Thus, the equilibrium constant has the following expression:

K_eq = [Ca^{2+][OH^-]^2 = K_{sp}

2. a. In the following problems, we'll be considering the common ion effect. According to the principle of Le Chatelier, an increase in concentration of any of the ions would shift the equilibrium towards the formation of our precipitate.

In this problem, we're adding calcium carbonate. It is insoluble, so it wouldn't have any effect on the equilibrium.

b. Sodium carbonate is completely soluble, it would release carbonate ions. The carbonate ions would combine with calcium cations and more precipitate would dissolve. This would shift the equilibrium towards formation of the products to reproduce the amount of calcium cations.                                      

c. HCl would neutralize calcium hydroxide to produce calcium chloride and water, so the amount of calcium ions would increase, therefore, the products are favored.

d. NaOH contains hydroxide anions, so we'd have a common ion. An increase in hydroxide would produce more precipitate, so our reactants are favored.

3 0
3 years ago
Brainliest will be given to correct answer :)
Lady_Fox [76]

Answer: \Delta G for the reaction   is -90kJ

Explanation:

The balanced chemical reaction is,

2H_2S(g)+SO_2(g)\rightarrow 3S_{rhombic}(s)+2H_2O(g)

The expression for Gibbs free energy change is,

\Delta G=[n\times G_{products}]-[n\times G_{reactants}]

Putting the values we get :

\Delta G=[3\times G_f{S,rhombic}+2\times G_f{H_2O}]-[2\times G_f{H_2S}+1\times G_f{SO_2}]

\Delta G=[(3\times 0kJ/mol)+(2\times -229kJ/mol)]-[(2\times -34kJ/mol) +(1\times -300kJ/mol)]

\Delta G=-90kJ

Thus \Delta G for the reaction2H_2S(g)+SO_2(g)\rightarrow 3S_{rhombic}(s)+2H_2O(g)   is -90kJ

5 0
3 years ago
22. Sodium-24 has a half-life of 15 hours. How much sodium-24 will remain in an 42.0-g sample after 90 hours?
N76 [4]

Answer:

The answer would be 0.65625

7 0
3 years ago
The boiling point of helium is 4 k. when helium boils, what interactions and/or bonds are overcome?
Kisachek [45]

Answer:

1.The boiling point of helium is 4 K. When helium boils, what interactions and/or bonds are...

1.The boiling point of helium is 4 K. When helium boils, what interactions and/or bonds are overcome?

2. The boiling point of hydrogen is 20 K. When hydrogen boils, what interactions and/or bonds are overcome?

3. What interactions and/or bonds are overcome when hydrogen at 30 K is heated to 6000 K?

Explanation:

7 0
3 years ago
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