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Mars2501 [29]
3 years ago
13

The solubility of silver sulfate (Ag2SO4), in moles per liter, can be expressed in terms of the resulting ion concentrations. Wh

ich relationship is correct?
Chemistry
1 answer:
lisabon 2012 [21]3 years ago
8 0

Answer:

Solubility = [SO₄²⁻]

Explanation:

Solubility of Ag₂SO₄ can be determined by its ksp equilibrium:

Ag₂SO₄(s) ⇄ SO₄²⁻ + 2Ag⁺

<em>Where 1 mole of silver sulfate dissolves producing 1 mole of sulfate ion and 2 moles of silver ion.</em>

Solubility is defined as the amount of solid that can be dissolved per liter of solution.

The moles of Ag₂SO₄ dissolved are equal to moles of SO₄²⁻.

That means:

<h3>Solubility = [SO₄²⁻]</h3>
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