Question

The solubility of silver sulfate (Ag2SO4), in moles per liter, can be expressed in terms of the resulting ion concentrations. Which relationship is correct?

Answer 1

Answer:

Solubility = [SO₄²⁻]

Explanation:

Solubility of Ag₂SO₄ can be determined by its ksp equilibrium:

Ag₂SO₄(s) ⇄ SO₄²⁻ + 2Ag⁺

Where 1 mole of silver sulfate dissolves producing 1 mole of sulfate ion and 2 moles of silver ion.

Solubility is defined as the amount of solid that can be dissolved per liter of solution.

The moles of Ag₂SO₄ dissolved are equal to moles of SO₄²⁻.

That means:

Solubility = [SO₄²⁻]