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jeka57 [31]
3 years ago
7

What is the largest object in the solar system

Physics
1 answer:
DENIUS [597]3 years ago
8 0

Answer: The largest object in the solar system would be the object in the middle because its mass bring smaller object into orbit. in our solar system that would be the Sun.

Explanation:

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An airplane accelerates from rest down a runway at 9.50 m/s2 for 29.3 seconds when it
Marat540 [252]

Answer:

Explanation:

s = ½at²

s = ½(9.50)(29.3²) = 4,077.8275

s = 4080 m

when rounded to the three significant digits of the question numerals.

8 0
3 years ago
How can you tell it's noon by looking at the earth's image?
Viefleur [7K]
But from either world, at any given time, you can see varying portions of that lighted half – or various phases of the Earth or moon. The phases are always the reverse of …
4 0
3 years ago
Calculate the kinetic energy in joules of a 1500 kg automobile moving at 17 m/s . express your answer to two significant figures
Sidana [21]
Kinetic energy = 1/2 (mass)*(velocity)^2

ke = 1/2 (1500kg) (17m/s)^2
ke = 216750 kg*m^2/s^2 = 216750 Joules

(sorry, I don't know significant figures. but this is otherwise the correct answer with the right units. hope this helps!! :))
6 0
4 years ago
A man walks 30 m to the west, then 5 m to the east in 45 seconds. What is his average speed?
dsp73

The average speed is  0.55 m/s

<h3>What was his displacement?</h3>

Displacement is defined as the change in position of an object.

Mathematically,

D = Initial value - Final Value

D = 30 - 5 = 25m

Now , We have to find the average velocity,

Average velocity is calculated by the formula V = D/t,

where V equals the average velocity, D equals total displacement and t equals total time.

V = D/t

V = 25 m / 45s

V = 0.55 m/s

So , The average speed is o.55 m/s

learn more about average speed:brainly.com/question/9834403

#SPJ1

5 0
2 years ago
A freshly prepared sample of radioactive isotope has an activity of 10 mCi. After 4 hours, its activity is 8 mCi. Find: (a) the
Maurinko [17]

Answer:

(a). The decay constant is 1.55\times10^{-5}\ s^{-1}

The half life is 11.3 hr.

(b). The value of N₀ is 2.38\times10^{11}\ nuclei

(c). The sample's activity is 1.87 mCi.

Explanation:

Given that,

Activity R_{0}=10\ mCi

Time t_{1}=4\ hours

Activity R= 8 mCi

(a). We need to calculate the decay constant

Using formula of activity

R=R_{0}e^{-\lambda t}

\lambda=\dfrac{1}{t}ln(\dfrac{R_{0}}{R})

Put the value into the formula

\lambda=\dfrac{1}{4\times3600}ln(\dfrac{10}{8})

\lambda=0.0000154\ s^{-1}

\lambda=1.55\times10^{-5}\ s^{-1}

We need to calculate the half life

Using formula of half life

T_{\dfrac{1}{2}}=\dfrac{ln(2)}{\lambda}

Put the value into the formula

T_{\dfrac{1}{2}}=\dfrac{ln(2)}{1.55\times10^{-5}}

T_{\dfrac{1}{2}}=44.719\times10^{3}\ s

T_{\dfrac{1}{2}}=11.3\ hr

(b). We need to calculate the value of N₀

Using formula of N_{0}

N_{0}=\dfrac{3.70\times10^{6}}{\lambda}

Put the value into the formula

N_{0}=\dfrac{3.70\times10^{6}}{1.55\times10^{-5}}

N_{0}=2.38\times10^{11}\ nuclei

(c). We need to calculate the sample's activity

Using formula of activity

R=R_{0}e^{-\lambda\times t}

Put the value intyo the formula

R=10e^{-(1.55\times10^{-5}\times30\times3600)}

R=1.87\ mCi

Hence, (a). The decay constant is 1.55\times10^{-5}\ s^{-1}

The half life is 11.3 hr.

(b). The value of N₀ is 2.38\times10^{11}\ nuclei

(c). The sample's activity is 1.87 mCi.

4 0
4 years ago
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