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Ksenya-84 [330]
3 years ago
11

A train travels at a velocuty of +50 m/s. it takes 8s to slow down to 5 m/s with constant acceleration. What was it's accelerati

on
Physics
2 answers:
Radda [10]3 years ago
7 0
5.635m/s2 is the acceleration of the train
Elena L [17]3 years ago
7 0
Acceleration = (v - u)/t        u = 50m/s, v = 5m/s, t = 8s

                       = (5 - 50) /8  = -45/8 = -5.625 m/s²


Acceleration = -5.625 m/s², so it actually decelerated by 5.625 m/s² because of the negative sign.
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10-kg box is sliding across an ice rink at 10 m/s . A skater exerts a constant force of 10 N against it. How long will it take f
Taya2010 [7]

Answer:

Time, t = 10 seconds

Explanation:

Given the following data;

Mass = 10kg

Force = 10N

Final velocity = 10m/s

Initial velocity = 0m/s

To find the time;

First of all, we would find the acceleration of the box.

Force = mass * acceleration

10 = 10 * acceleration

Acceleration = 10/10 = 1m/s²

Now, we can find the time by using the first equation of motion;

V = U + at

10 = 0 + 1t

10 = t

Time, t = 10 seconds

Therefore, it will take 10 seconds for the box to come to a complete stop.

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3 years ago
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ycow [4]

Answer b

Explanation:

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5 0
3 years ago
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I'm doing a presentation over real-world applications of physics and the group I am in wants to do "the physics of video games"
artcher [175]
Most modern games have a sense of real-world physics, but not exactly perfect. In a video game, the realistic movement or action greatly depends on the precision of coding. In real life, movement isn't done or programmed by a strand of code.

Your presentation sounds interesting, being a gamer myself, I would look forward to it. But the choice lies in your hands. If you do reconsider, be sure you have a backup plan. Good luck to you.
3 0
3 years ago
A uniform electric field exists in the region between two oppositely charged plane-parallel plates. An electron is released from
Zigmanuir [339]

Answer:

Explanation:

  • given S = distance from the first = 3.20cm = 0.032m, t = 1.30×10−8 s
  • q = 1.6 x 10_19C
  • using S = at^2/2
  • acceleration = 0.032 X 2 /(1.30×10−8)^2

a = 3.79 x 10^14m/s^2

  • From F = ma
  • F = qE
  • ma = qE

E = ma /q = 9.11 x 10^-31 x 3.79 x 10^14 / 1.6 x 10^-19

E = magnitude of this electric field. = 2156.3N/C

b) Find the speed of the electron when it strikes the second plate ; V^2 = 2as

= 2 X 3.79 x 10^14 X 0.032

= 4.92 X 10^6m/s

5 0
3 years ago
Suppose 8.41 moles of a monatomic ideal gas expand adiabatically, and its temperature decreases from 395 to 279 K. Determine (a)
sergeinik [125]

Answer:

a) W=12166.20876 J

b) U= -12166.20876 J

Explanation:

No. of moles, n = 8.41

Change of temperature, ΔT = T1 - T2

                                         = 395 - 279

                                         = 116 K

For monatomic gas, γ = 5/3

γ -1 = 2 /3

Solution:

(a)

Work done,W= \frac{nR}{\gamma-1}(T_1-T_2)

plugging values we get

W= \frac{8.314\times8.41}{2/3}(116)

Ans:   12166.20876 J

Work done, W = + 12166.20876 J

(b)

From first law of thermodynamics, dQ = U + W

but, dQ = 0 ( adiabatic process)

Hence, U = - W

                 = - 12166.20876 J

Ans:

Change in internal energy, U = - 12166.20876 J

8 0
3 years ago
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