Answer: required tensile stress is 0.889 MPa
Explanation:
Given that;
tensile load is oriented along the [1 1 1] direction
shear stress is 0.242 MPa along [1 0 1] in the (1 1 -1) plane
first we determine
λ which is Angle between  [1 1 1]  and  [1 0 1]
so
cosλ = [ 1(1) +  1(0) + 1(1) ] / [ √(1² + 1² + 1²) √(1² + 0² + 1²)]
= 2 / √3√2 =  2/√6
Next, we determine ∅ which is angle between [1 1 1]  and  [1 1 -1]
so,
cos∅ = [ 1(1) +  1(1) + 1(-1) ] / [ √(1² + 1² + 1²) √(1² + 1² + (-1)²)]
cos∅ = [ 2-1] / [√3√3 ]
cos∅ = 1/3
Now, we know that;
σ = T_stress/cosλcosθ
so we substitute
σ = 0.242 / ( 2/√6 × 1/3 )
σ = 0.242 / 0.2721
σ = 0.889 MPa
Therefore, required tensile stress is 0.889 MPa
 
        
             
        
        
        
Answer: ok the best one would be letter s because it goes
Explanation:
467,,mm tubing should do
 
        
             
        
        
        
Answer:
15,000 psi
Explanation:
The solution / solving is attach below.
 
        
             
        
        
        
Answer:
All the detailed steps are mentioned in pictures. 
Explanation:
See attached pictures.