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KIM [24]
3 years ago
6

The following sentence can be categorized as what stage in the Scientific Method: Abraham notices that Saharan desert ants will

take great distances when looking for food, however once return from their journey they will take the shortest distance possible (straight line) to get back to their niche.
Engineering
1 answer:
Marat540 [252]3 years ago
6 0

Answer:

Saharan desert ants is making observations

Explanation:

The Saharan desert ants are using every available opportunity to make observations in search of food and that's the reason why they take great distances. However, after getting food, they are always eager to return back to their niche as soon as possible.

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An AC generator supplies an rms voltage of 120 V at 50.0 Hz. It is connected in series with a 0.650 H inductor, a 4.80 μF capaci
Serggg [28]

Answer:

Explanation:

f = 50.0 Hz, L = 0.650 H, π = 3.14

C = 4.80 μF, R = 301 Ω resistor. V = 120volts

XL = wL = 2πfL

= 2×3.14×50* 0.650

= 204.1 Ohm

Xc= 1/wC

Xc = 1/2πfC

Xc = 1/2×3.14×50×4.80μF

= 1/0.0015072

= 663.48Ohms

1. Total impedance, Z = sqrt (R^2 + (Xc-XL)^2)= √ 301^2+ (663.48Ohms - 204.1 Ohm)^2

√ 90601 + (459.38)^2

√ 90601+211029.98

√ 301630.9844

= 549.209

Z = 549.21Ohms

2. I=V/Z = 120/ 549.21Ohms =0.218Ampere

3. P=V×I = 120* 0.218 = 26.16Watt

Note that

I rms = Vrms/Xc

= 120/663.48Ohms

= 0.18086A

4. I(max) = I(rms) × √2

= 0.18086A × 1.4142

= 0.2557

= 0.256A

5. V=I(max) * XL

= 0.256A ×204.1

=52.2496

= 52.250volts

6. V=I(max) × Xc

= 0.256A × 663.48Ohms

= 169.85volts

7. Xc=XL

1/2πfC = 2πfL

1/2πfC = 2πf× 0.650

1/2×3.14×f×4.80μF = 2×3.14×f×0.650

1/6.28×f×4.8×10^-6 = 4.082f

1/0.000030144× f = 4.082×f

1 = 0.000030144×f×4.082×f

1 = 0.000123f^2

f^2 = 1/0.000123048

f^2 = 8126.922

f =√8126.922

f = 90.14 Hz

8 0
3 years ago
An electric power plant uses solid waste for fuel in the production of electricity. The cost Y in dollars per hour to produce el
andrew-mc [135]

Answer:

15.64 MW

Explanation:

The computation of value of X that gives maximum profit is shown below:-

Profit = Revenue - Cost

= 15x - 0.2x 2 - 12 - 0.3x - 0.27x 2

= 14.7x - .47x^2 - 12

After solving the above equation we will get maximum differentiate  for profit that is

14.7 - 0.94x = 0

So,

x = 15.64 MW

Therefore for computing the value of X that gives maximum profit we simply solve the above equation.

8 0
3 years ago
Alyssa works for an engineering firm that has been hired to design and supervise the construction of a highway bridge over a maj
Colt1911 [192]

Answer:

I'm going to make a list of everything you need to consider for the supervision and design of the bridge.

1. the materials with which you are going to build it.

2. the length of the bridge.

3. The dynamic and static load to which the bridge will be subjected.

4. How corrosive is the environment where it will be built.

5.wind forces

6. The force due to possible earthquakes.

7. If it is going to be built in an environment where snow falls.

8. The bridge is unique,so   the shape has a geometry that resists loads?.

9. bridge costs.

10. Personal and necessary machines.

11. how much the river grows

3 0
3 years ago
Two particles have a mass of 7.8 kg and 11.4 kg , respectively. A. If they are 800 mm apart, determine the force of gravity acti
aleksley [76]

Answer:

A) About 9.273 \times 10^{-9} newtons

B) 76.518 newtons

C) 111.834 newtons

Explanation:

A) F_g=\dfrac{GM_1M_2}{r^2} , where G is the universal gravitational constant, M 1 and 2 are the masses of both objects in kilograms, and r is the radius in meters. Plugging in the given numbers, you get:

F_g=\dfrac{(6.67408 \times 10^{-11})(7.8)(11.4)}{(0.8)^2}\approx 9.273 \times 10^{-9}

B) You can find the weight of each object on Earth because you know the approximate acceleration due to gravity is 9.81m/s^2. Multiplying this by the mass of each object, you get a weight for the first particle of 76.518 newtons.

C) You can do a similar thing to the previous particle and find that its weight is 11.4*9.81=111.834 newtons.

Hope this helps!

3 0
3 years ago
Socket Programming: (30 points) Use Python TCP socket to implement an application with client-server architecture. In this appli
ololo11 [35]

Answer:

Explanation:

Run the code given in text file following instructions.

Download txt
8 0
3 years ago
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