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Ostrovityanka [42]
3 years ago
14

While discussing what affects the amount of pressure exerted by the brakes: Technician A says that the shorter the line, the mor

e pressure there will be. Technician B says that braking force will increase if the size of the pistons in a master cylinder are increased. Who is correct?
Engineering
1 answer:
harina [27]3 years ago
5 0

Answer:

Only Technician B is right.

Explanation:

The cylindrical braking system for a car works through the mode of pressure transmission, that is, the pressure applied to the brake pedals, is transmitted to the brake pad through the cylindrical piston.

Pressure applied on the pedal, P(pedal) = P(pad)

And the Pressure is the applied force/area for either pad or pedal. That is, P(pad) = Force(pad)/A(pad) & P(pedal) = F(pedal)/A(pedal)

If the area of piston increases, A(pad) increases and the P(pad) drops, Meaning, the pressure transmitted to the pad reduces. And for most cars, there's a pressure limit for the braking system to work.

If the A(pad) increases, P(pad) decreases and the braking force applied has to increase, to counter balance the dropping pressure and raise it.

This whole setup does not depend on the length of the braking lines; it only depends on the applied force and cross sectional Area (size) of the piston.

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Cual es el impacto medioambiental del mortero?
ddd [48]

Explanation:

La industria del acero desecha gran cantidad de polvos, los que acopiados al aire libre, sobre el suelo y sometidos a ¡a acción de los agentes climáticos, contaminan el medio ambiente. El propósito del presente trabajo es evaluar el impacto ambiental que produce la incorporación de polvos de acería a matrices de cemento portland, sometidas a condiciones de humedad, presión y temperatura. Se caracterizó químicamente el material de desecho de una acería de Argentina, para identificar los elementos presentes. Por difractometría de rayos X (XRD) se determinaron las estructuras de las sustancias y su grado de oxidación. Se utilizó SEM-EDAX con el propósito de observar forma, tamaño y composición química de las partículas. Se elaboraron diferentes morteros de cemento Portland y se incorporó este material en diferentes porcentajes. Se moldearon probetas normalizadas para realizar ensayos mecánicos, de lixiviación y estudios petrográficos. Se analizó la composición química del agua de curado de las probetas y del líquido obtenido en ensayos de lixiviación. Los resultados permitieron identificar y cuantificar los elementos peligrosos que pueden se incorporados al ambiente y sugerir medidas de prevención.

3 0
3 years ago
Ammonia enters the expansion valve of a refrigeration system at a pressure of 10 bar and a temperature of 20oC and exits at 3.0
icang [17]

Answer:

Ammonia enters the expansion valve of a refrigeration system at a pressure of 10 bar and a temperature of 20 o C and exits at 5.0 bar. The refrigerant undergoes a throttling process. Determine the temperature, in o C, and the quality of the refrigerant at the exit of the expansion valve.

Explanation:

3 0
3 years ago
A light bar AD is suspended from a cable BE and supports a 20-kg block at C. The ends A and D of the bar are in contact with fri
babymother [125]

Answer:

Tension in cable BE= 196.2 N

Reactions A and D both are  73.575 N

Explanation:

The free body diagram is as attached sketch. At equilibrium, sum of forces along y axis will be 0 hence

T_{BE}-W=0 hence

T_{BE}=W=20*9.81=196.2 N

Therefore, tension in the cable, T_{BE}=196.2 N

Taking moments about point A, with clockwise moments as positive while anticlockwise moments as negative then

196.2\times 0.125- 196.2\times 0.2+ D_x\times 0.2=0

24.525-39.24+0.2D_x=0

D_x=73.575 N

Similarly,

A_x-D_y=0

A_x=73.575 N

Therefore, both reactions at A and D are 73.575 N

7 0
3 years ago
Air, at a free-stream temperature of 27.0°C and a pressure of 1.00 atm, flows over the top surface of a flat plate in parallel f
Morgarella [4.7K]

Answer:

Explanation:

Given that:

V = 12.5m/s

L= 2.70m

b= 0.65m

T_{ \infty} = 27^0C= 273+27 = 300K

T_s= 127^0C = (127+273)= 400K

P = 1atm

Film temperature

T_f = \frac{T_s + T_{\infty}}{2} \\\\=\frac{400+300}{2} \\\\=350K

dynamic viscosity =

\mu =20.9096\times 10^{-6} m^2/sec

density = 0.9946kg/m³

Pr = 0.708564

K= 229.7984 * 10⁻³w/mk

Reynolds number,

Re = \frac{SUD}{\mu} =\frac{\ SUl}{\mu}

=\frac{0.9946 \times 12.5\times 2.7}{20.9096\times 10^-^6} \\\\Re=1605375.043

we have,

Nu=\frac{hL}{k} =0.037Re^{4/5}Pr^{1/3}\\\\\frac{h\times2.7}{29.79\times 10^-63} =0.037(1605375.043)^{4/5}(0.7085)^{1/3}\\\\h=33.53w/m^2k

we have,

heat transfer rate from top plate

\theta _1 =hA(T_s-T_{\infty})\\\\A=Lb\\\\=2.7*0.655\\\\ \theta_1=33.53*2.7*0.65(127/27)\\\\ \theta_1=5884.51w

7 0
3 years ago
A closed vessel of volume 80 litres contain gas at a gauge pressure of 150 kPa. If the gas is compressed isothermally to half it
horsena [70]

Answer:

The resulting pressure is 300 kilopascals.

Explanation:

Let consider that gas within the closed vessel behaves ideally. By the equation of state for ideal gases, we construct the following relationship for the isothermal relationship:

P_{1}\cdot V_{1} = P_{2} \cdot V_{2} (1)

Where:

P_{1}, P_{2} - Initial and final pressure, measured in kilopascals.

V_{1}, V_{2} - Initial and final volume, measured in litres.

If we know that \frac{V_{1}}{V_{2}} = 2 and P_{1} = 150\,kPa, then the resulting pressure is:

P_{2} = P_{1}\times \frac{V_{1}}{V_{2}}

P_{2} = 300\,kPa

The resulting pressure is 300 kilopascals.

6 0
3 years ago
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