Answer:
A double-entry bookkeeping system is where a corresponding entry is made for every transaction.
Answer:
a) Vout= 5V
b) Vout= 5V
c) Vbase= 0.6V
d) Vbase= 0.6V
Explanation:
Consider the circuit shown in attachment
a) When Vin is 0V, the base circuit is not turned, so
Ib=0 and Ic=∞ as transistor is not turned on so
Vout =5V
b) When Vin= 5 V,
Ib= (Vin-Vb)/Rb
Ib=(5-0.6)/1000= 0.0044A
Ic= 0.0044×10=0.044A
Vout= 5- 0.044×1000= not real value
Vout= Vce= 5V
c) voltage drop across Vbase= 0.6V
d) Vbase= 0.6V
In all the above cases, the transistor will not be turned on biasing base voltage and resistor values are very high compared to VCC which is 5V in the given circuit
Answer:
kinetic energy means energy which a body possesses by virtue of being in motion
Answer:
hello your question lacks the required image attached to this answer is the image required
answer : NOR1(q_) wave is complementary to NOR2(q)
Explanation:
Note ; NOR 2 will be addressed as q in the course of this solution while NOR 1 will be addressed as q_
Initial state is unknown i.e q = 0 and q_= 1
from the diagram the waveform reset and set
= from 0ns to 20ns reset=1 and set=0.from the truth table considering this given condition q=0 and q_bar=1 while
from 30ns to 50ns reset=0 and set=1.from the truth table considering this condition q=1 and q_bar=1.so from 35ns also note there is a delay of 5 ns for the NOR gate hence the NOR 2 will be higher ( 1 )
From 50ns to 65ns both set and reset is 0.so NOR2(q)=0.
From 65 to 75 set=1 and reset=0,so our NOR 2(q)=1 checking from the truth table
also from 75 to 90 set=1 and reset=1 , NOR2(q) is undefined "?" and is mentioned up to 95ns.
since q_ is a complement of q, then NOR1(q_) wave is complementary to NOR2(q)