A good rule of thumb in hazardous conditions is to _____.
2 answers:
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Answer:
ordinary bulb total cost is $39.54
fluorescent bulb total cost is $13.05
amount save = 39.54 - 13.05 = $26.49
resistance = 626.1 ohm
Explanation:
in the 1st part
bulb on time = 3 year = 4380 hours
life of bulb = 750 h
so number of bulb required =
number of bulb required = 6
cost of 6 bulb is = 6 × 0.75 = $4.5
so
cost of operation is = 100 × 4380 ×
cost of operation = $35.04
so total cost will be = $4.5 + $35.04 = $39.54
and
when compare with florescent bulb
time = 3 year = 4380 h
life of bulb = 10000 h
so number of bulb required =
number of bulb required = 0.43 = 1
cost of 6 bulb is = 1 × 5 = $5
so
cost of operation is = 23 × 4380 ×
cost of operation = $8.05
so total cost will be = $5 + $8.05 = $13.05
in part 2nd
total amount save while compare bulb is
amount save = 39.54 - 13.05 = $26.49
and in part 3rd
resistance of bulb is
resistance =
resistance =
resistance = 626.1 ohm
Answer:
vB = - 0.176 m/s (↓-)
Explanation:
Given
(AB) = 0.75 m
(AB)' = 0.2 m/s
vA = 0.6 m/s
θ = 35°
vB = ?
We use the formulas
Sin θ = Sin 35° = (OA)/(AB) ⇒ (OA) = Sin 35°*(AB)
⇒ (OA) = Sin 35°*(0.75 m) = 0.43 m
Cos θ = Cos 35° = (OB)/(AB) ⇒ (OB) = Cos 35°*(AB)
⇒ (OB) = Cos 35°*(0.75 m) = 0.614 m
We apply Pythagoras' theorem as follows
(AB)² = (OA)² + (OB)²
We derive the equation
2*(AB)*(AB)' = 2*(OA)*vA + 2*(OB)*vB
⇒ (AB)*(AB)' = (OA)*vA + (OB)*vB
⇒ vB = ((AB)*(AB)' - (OA)*vA) / (OB)
then we have
⇒ vB = ((0.75 m)*(0.2 m/s) - (0.43 m)*(0.6 m/s) / (0.614 m)
⇒ vB = - 0.176 m/s (↓-)
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