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Ymorist [56]
2 years ago
8

A good rule of thumb in hazardous conditions is to _____.

Engineering
2 answers:
Svet_ta [14]2 years ago
7 0
I think the answer is c
Aloiza [94]2 years ago
5 0

Answer:

C. Have your hazard lights on

Explanation:

Speeding up will cause an accident

Counter steering is not easy to do

Slowing down my result in you being rear ended

You might be interested in
How many watts are consumed in a circuit having a power factor of 0. 2 if the input is 100 vac at 4 amperes?.
Anna71 [15]

The watts that are consumed is 80 watts.

<h3>What power factor?</h3>

The term power factor has to do with the measure of the efficiency of the use of energy. Recall that power is defined as the rate of doing work. The magnitude of the power factor shows the extent to which the power is used.

Now, to obtain the watts are consumed in a circuit having a power factor of 0. 2 if the input is 100 vac at 4 amperes we have;  V × I × PF = 100V × 4A × 0.2 = 80 watts.

Learn more about power factor:brainly.com/question/10634193

#SPJ4

6 0
1 year ago
(3) Calculate the heat flux through a sheet of brass 7.5 mm (0.30 in.) thick if the temperatures at the two faces are 150°Cand 5
bezimeni [28]

Answer:

a.) 1.453MW/m2,  b.)  2,477,933.33 BTU/hr  c.) 22,733.33 BTU/hr  d.) 1,238,966.67 BTU/hr

Explanation:

Heat flux is the rate at which thermal (heat) energy is transferred per unit surface area. It is measured in W/m2

Heat transfer(loss or gain) is unit of energy per unit time. It is measured in W or BTU/hr

1W = 3.41 BTU/hr

Given parameters:

thickness, t = 7.5mm = 7.5/1000 = 0.0075m

Temperatures 150 C = 150 + 273 = 423 K

                        50 C = 50 + 273 = 323 K

Temperature difference, T = 423 - 323 = 100 K

We are assuming steady heat flow;

a.) Heat flux, Q" = kT/t

K= thermal conductivity of the material

The thermal conductivity of brass, k = 109.0 W/m.K

Heat flux, Q" = \frac{109 * 100}{0.0075} = 1,453,333.33 W/m^{2} \\ Heat flux, Q" = 1.453MW/m^{2} \\

b.) Area of sheet, A = 0.5m2

Heat loss, Q = kAT/t

Heat loss, Q = \frac{109*0.5*100}{0.0075} = 726,666.667W

Heat loss, Q = 726,666.667 * 3.41 = 2,477,933.33 BTU/hr

c.) Material is now given as soda lime glass.

Thermal conductivity of soda lime glass, k is approximately 1W/m.K

Heat loss, Q=\frac{1*0.5*100}{0.0075} = 6,666.67W

Heat loss, Q = 6,666.67 * 3.41 = 22,733.33 BTU/hr

d.) Thickness, t is given as 15mm = 15/1000 = 0.015m

Heat loss, Q=\frac{109*0.5*100}{0.015} =363,333.33W

Heat loss, Q = 363,333.33 * 3.41 = 1,238,966.67 BTU/hr

5 0
2 years ago
A closed system consists of 0.3 kmol of octane occupying a volume of 5 m³. Determine (a) the weight of the system, in N, and (b)
Leni [432]

Answer:

a) m=336.18N

b) Vn=16.67m/kmol

Vm=0.1459m^3/kg

Explanation:

To calculate the mass of the octane(m):

Number of mole of octane (n) =0.3kmol(given)

Molarmass of octane (M) =114.23kg/kmol

m=n*M

m=(0.3kmol)*(114.23kg/kmol)

m=34.269kg

To calculate for the weight of octane(W):

W=g*m

W=(9.81m/s^2)*(34.269kg)

W=336.18N

b) For specific volumes of Vn and Vm:

Given volume of octane (V) =5m^3

Vm=V/m

Vm=5m^3/34.269kg

Vm=0.1459m^3/kg

And Vn will be :

Vn=V/m=5m^3/0.3kmol

Vn=16.67m/Kmol

Therefore, the answers are:

a) m=336.18N

b) Vn=16.67m/kmol

Vm=0.1459m^3/kg

7 0
3 years ago
The Air Force One (Boeing 747-200) has a long-range mission takeoff gross load 833,000 pounds (Ibm). What is Air Force One's tak
Ahat [919]

Answer:

The mass in:

1) Grams =377765.5\times 10^{3}grams

2) Kilograms =377765.5kilograms

3)Tonnes =377.7655tonnes

4) Megatonnes =0.378megatonnes

Explanation: The given mass of the aircraft in pounds is 833,000 pounds.

Part 1)

Since we know that 1 pound equals 453.5 grams thus by ratio we have

833,000 pounds =833000lb\times 453.5\frac{g}{lb}=377765.5\times 10^{3}grams

Part 2)

Since we know that 1000 grams equals 1 kilogram

thus the above mass in kilograms equals\frac{377765.5\times 10^{3}}{1000}=377765.5kg

Part 3)

Since there are 1000 kilograms in 1 tonne

thus the given mass is converted into tonnes as

mass_{tonnes}=\frac{377765.5kg}{1000}=377.765tonnes

Part 4)

Since 1 Mega tonne(Mton) equals 1000 tonnes thus the given mass is converted into mega tonnes as

mass_{M\cdot tonn}=\frac{377.7655tonnes}{1000}=0.378Megatonnes

4 0
3 years ago
Decide whether or not the Final Value Theorem is applicable to the following functions. If not, indicate why you cannot apply it
LUCKY_DIMON [66]

Answer:

a) Yes applicable, x(∞) = 0

b) Yes applicable, x(∞) = 0

Explanation:

Final Value Theroem indicates that final value of x(t) can be found by Laplace Transform X(s) as follows:

x(\infty)= \lim\limits_{s \to0} sX(s)

a) X(s)= \frac{s}{3s+7}

Since the pole is at left side, FVT is applicable

x(\infty)= \lim\limits_{s \to0} s\frac{s}{3s+7}=0

b) X(s)= \frac{10}{3s^2+7s+4}

\frac{10}{3s^2+7s+4}= \frac{10}{(3s+4 )(s+1)}

Since the poles are at left side, FVT is applicable

x(\infty)= \lim\limits_{s \to0} s \frac{10}{(3s+4 )(s+1)}=0

3 0
2 years ago
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