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Ymorist [56]
3 years ago
8

A good rule of thumb in hazardous conditions is to _____.

Engineering
2 answers:
Svet_ta [14]3 years ago
7 0
I think the answer is c
Aloiza [94]3 years ago
5 0

Answer:

C. Have your hazard lights on

Explanation:

Speeding up will cause an accident

Counter steering is not easy to do

Slowing down my result in you being rear ended

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Health Maintenance Organizations (HMOs) are the new model for providing medical care. Criticisms of HMOs include all of the foll
Tema [17]

Answer:

c. multiple trips to many specialists.

Explanation:

These are a organizations that provide health insurance time fee.

7 0
4 years ago
Write a function MaxMagnitude() with two integer input parameters that returns the largest magnitude value. Use the function in
Svetradugi [14.3K]

Answer:

The function requires evaluate the largest magnitude (the largest value withou sign), so we need to compare the absolute value of the two inputs number. For that we use the abs() function.

The code is as follows, with the comments after // and in italic font:

#include <iostream>   <em>//module for input/output stream objects</em>

#include <cmath>  <em>//math module </em>

using namespace std;

<em>// follows the function definition  </em>

int MaxMagnitude (int userVal1, int userVal2) {

 int Max=0;    <em>//define output variable Max</em>

 if (abs(userVal1) > abs(userVal2)) {  <em>// compare magnitude </em>

   Max = userVal1;  <em> //if Val1 is larger than val2 Max is Val1</em>

 }

 else {

   Max = userVal2;  <em>//else the max is Val 2 </em>

 }

 return Max;  <em>//the value returned for this function</em>

 }

// <em>in main we will use the defined function MaxMagnitude</em>

int main() {

  int one = 0;

 int two = 0;

 cin >> one;  //assignation of the first user input to one  

 cin >> two;   //assignation of the second user input to two  

//we call the function using as input the read values

//and write the return of the function, all at once  

  cout << MaxMagnitude(one, two) << endl;  

  return 0;

}

3 0
3 years ago
After one side of the stock is planed to a true surface, it is usually
stiv31 [10]
Answer:

Maybe your answer is B
7 0
4 years ago
Two cars are traveling on level terrain at 55 mi/h on a road with a coefficient of adhesion of 0.75. The driver of car 1 has a 2
Vlad1618 [11]

Answer:

0.981

Explanation:

velocity  of cars ( v1 , v2 )  = 55 mi/h

coefficient of adhesion ( u ) = 0.75

Reaction time of driver of car 1 = 2.3 -s

Reaction time of driver of car 2 = 1.9 -s

breaking efficiency of car 2 ( n2 ) = 0.80

<u>Determine the braking efficiency of car 1</u>

First determine the distance travelled during reaction time ( dr )

dr = v * tr ------- ( 1 )

tr ( reaction time )

v = velocity

note : 1 mile = 1609 m ,  I hour = 60 * 60 secs

<em>back to equation 1</em>

for car 1

dr1 =( 55 * 2.3 * 1609 ) / ( 60 * 60 )

    = 56.53 m

for car 2

dr2 = ( 55 * 1.9 * 1609 ) / ( 60 * 60 )

   = 46.70 m

<em>next we calculate the stopping distances  ( d ) using the relation below</em>

ds = d + dr

 d = distance travelled during break

 dr = distance travelled during reaction time

where : d = \frac{v^2intial}{2ugn}

<em>for car 1 </em>

d1 = \frac{(55)^2}{2*0.75*9.81* n1} * (\frac{1609}{3600} )^2

∴ d1 = \frac{41.10}{n1}

<em>for car 2 </em>

d2 = \frac{(55)^2}{2*0.75*9.8*0.8} * (\frac{1609}{3600} )^2

∴ d2 = 51.38

since the stopping distance for both cars are the same

d1 + dr1 = d2 + dr2

( 41.10 /n1 ) + 56.53 = 51.38 + 46.70

solve for n1

hence n1 = 0.981 ( braking efficiency of car 1 )

4 0
3 years ago
What does self-consolidating concrete not need?
Klio2033 [76]

Answer:

Self-consolidating concrete does not need: Vibrating Given a proper gradation of satisfactory aggregates, the strength of cured concrete is primarily dependent on the amount of cement in the mix and on the water-cement (w-c or W/C) ratio. The higher the water-cement ratio the higher concrete strength. False

6 0
3 years ago
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