Answer:
The formula of the compound formed by Iron (ii) ions and chromate ions is FeCrO₄
Explanation:
Iron (ii) ions, Fe²⁺ have a positive charge of +2. Chromate ions, CrO₄²⁻, on the other hand have a positive charge of -2. When iron (ii) ions and chromate ions combine two form a compound, each ion will contribute a mole of ion towards the formation of the compound. This is in line with the idea that a compound carries no charge. The positive charge (+2) of the iron (ii) ions are balanced by the negative charge of the chromate ions as shown mathematically as follows;
+2 + (-2) = 0; i.e. Fe²⁺ + CrO₄²⁻ = FeCrO₄
Therefore, the formula of the compound formed by Iron (ii) ions and chromate ions is FeCrO₄
Answer:
The phenotypic percentage of having yellow or green seeds is 50% for having either of the two colours
Explanation:
The crossing to determine the offsprings is shown in the image attached where we have two green (Yy) seeds and two yellow (yy) seeds as offsprings.
Thus, <u>the phenotypic percentage of having yellow or green seeds is 50% for having either of the two colours</u>.
Note, the dominant allele is "Y" while the recessive allele is "y". Thus, Yy would produce a yellow colour while yy would produce a green colour (as both mentioned in the question).
Also note that phenotype describes the outward properties/characteristics of an individual.
Answer:
The new pH of the solution 
Explanation:
Given
pH of bottle of Soda is 
As we know that
pH
log [H+]
We will derive the hydrogen ion concentration when pH is 
log [H+]
Taking anti-log on both the sides, we get -
H+ ion is equal to 
When the hydronuim ion concentration reduces by
of the original concentration, the new hydrogen ion concentration becomes

The new pH is
![= - log [ 10^{-6}]\\= 6](https://tex.z-dn.net/?f=%3D%20-%20log%20%5B%2010%5E%7B-6%7D%5D%5C%5C%3D%206)