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3 years ago

Explain why a valve would last longer in the pulmonary position than in the aortic position

1 answer:

4 0

Answer:The pulmonary valve is usually under less stress because the right pumping chamber does not need to generate as much force to push blood to the lungs. Therefore, a replacement valve can be more likely to succeed in the pulmonary position because demand on this valve is less.

Explanation:

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Particle 1 has mass 4.6 kg and is on the x-axis at x = 5.7 m. Particle 2 has mass 7.2 kg and is on the y-axis at y = 4.2 m. Part

Iteru [2.4K]

To solve this problem it is necessary to apply the concepts related to the Gravitational Force, for this purpose it is understood that the gravitational force is described as

$F_g = \frac{Gm_1m_2}{r^2}$

Where,

G = Gravitational Universal Force

$m_i =$ Mass of each object

To solve this problem it is necessary to divide the gravitational force (x, y) into the required components and then use the tangent to find the angle generated between both components.

Our values are given as,

$m_1 =4.6 kg\\m_2 = 7.2 kg\\m_3 = 2.6 kg\\r_1 = 5.7 m\\r_2 = 4.2 m$

Applying the previous equation at X-Axis,

$F_x = \frac{Gm_1m_3}{R_{1}^2}\\F_x = \frac{6.67*10^{-11}*4.6*2.6}{5.7^2}\\F_x = 2.46*10^{-11}N$

Applying the previous equation at Y-Axis,

$F_y = \frac{Gm_2m_3}{R_2^2}\\F_y = \frac{6.67*10^{-11}*7.2*2.6}{4.2^2}\\F_y = 7.08*10^{-11} N$

Therefore the angle can be calculated as,

$tan\theta = \frac{F_y}{F_x}\\\theta = tan^{-1} \frac{F_y}{F_x}\\\theta = tan^{-1} \frac{7.08*10^{-11}}{2.46*10^{-11}}\\\theta = 71\°$

Then in the measure contrary to the hands of the clock the Force in the particle 3 is in between the positive direction of the X and the negative direction of the Y at 71 ° from the positive x-axis.

5 0

4 years ago

What is the validity of v=2Rg

Anarel [89]

There's no possible way to think about the validity of that equation until we know what the variables v, R, and g represent.

8 0

3 years ago

A car was traveling at 20m/s and slammed on the brakes causing the car to decelerate at a rate of -2.5 m/s^2 before coming to a

Taya2010 [7]

Answer: 160 m

Explanation: First find time or t using the formula for acceleration:

a = vf - vi / t

So t is equal to:

t = vf - vi / a

= 0 m/s - 20 m/s / -2.5 m/s²

= 8 s

To find the distance use the formula for velocity:

v = d / t

Derive for d:

d = v x t

= 20 m/s x 8 s

= 160 m

5 0

3 years ago

Hey I need help w/ this pic below ASAP!!!<br> Pls will mark brainliest:) Not joking lol

Arturiano [62]

Where is the picture

4 0

3 years ago

Read 2 more answers

A microphone is attached to a spring that is suspended from the ceiling, as the drawing indicates. Directly below on the floor i

Nutka1998 [239]

Answer:

$0.361\ \text{m}$

Explanation:

$f_s$ = Frequency of source = 375 Hz

$\Delta f$ = Difference between the maximum and minimum sound frequencies = 2.75 Hz

v = Speed of sound in air = 343 m/s

T = Time period = 1.8 s

$v_m$ = Maximum speed of the microphone

We have the relation

$\Delta f=2f_s\dfrac{v_m}{v}\\\Rightarrow v_m=\dfrac{\Delta fv}{2f_s}\\\Rightarrow v_m=\dfrac{2.75\times 343}{2\times 375}\\\Rightarrow v_m=1.26\ \text{m/s}$

Amplitude is given by

$A=\dfrac{v_mT}{2\pi}\\\Rightarrow A=\dfrac{1.26\times 1.8}{2\pi}\\\Rightarrow A=0.361\ \text{m}$

The amplitude of the simple harmonic motion is $0.361\ \text{m}$ .

5 0

3 years ago