2 years ago

• A plastic bag filled with air has a volume of

Physics

1 answer:

ratelena [41]2 years ago

8 0

Answer:

The change in the mass of box = 0.01 kg

Volume of air in the polythene bag = Volume of air in the rigid box

Therefore, Volume of air in the box = 0.008 m^3

Now, Density = Mass/ Volume

=> Density = 0.01 / 0.008 = 1.25 Kg / m^3

Explanation:

I looked it up

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The electric field strength between the plates of a simple air capacitor is equal to the voltage across the plates divided by th

Dmitry [639]

Answer:

d = V/E

Explanation:

From the definition, we can say that the electric field strength between the plates of a parallel plate capacitor is

E = v/d

where

E = electric field strength

V = potential difference

d = distance between the plates

On rearranging the equation and making d subject of the formula, we have

d = V/E

From the question, we're given that

V = 112 V

E = 1.12 kV/cm converting to V/m, we have 110000 V/cm

d = 112 / 110000

d = 0.00102 m

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3 years ago

A car accelerates from rest at a rate of 6.50 m/s2. Determine thevelocity of the car at t = 4.00 s.

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Answer:

1.62 m/s2

Explanation:

6.50 divided by 4

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2 years ago

How do you calculate the total resistance of a series circuit

CaHeK987 [17]

Add all the resistances across the circuit together the calculate the total resistance

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3 years ago

In a closed system, _____ energy is equal to potential energy plus kinetic energy.

Kobotan [32]

The answer is mechanical

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3 years ago

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An airplane traveling at half the speed of sound emits a sound of frequency 4.68 kHz. (a) At what frequency does a stationary li

kkurt [141]

Answer:

(a) 9.36 kHz

(b) 3.12 kHz

Explanation:

(a)

V = speed of sound

$v$ = speed of airplane = (0.5) V

f = actual frequency of sound emitted by airplane = 4.68 kHz = 4680 Hz

f' = Frequency heard by the stationary listener

Using Doppler's effect

$f' = \frac{Vf}{V-v}$

$f' = \frac{V(4680)}{V-(0.5)V)}$

f' = 9360 Hz

f' = 9.36 kHz

(b)

V = speed of sound

$v$ = speed of airplane = (0.5) V

f = actual frequency of sound emitted by airplane = 4.68 kHz = 4680 Hz

f' = Frequency heard by the stationary listener

Using Doppler's effect

$f' = \frac{Vf}{V+v}$

$f' = \frac{V(4680)}{V+(0.5)V)}$

f' = 3120 Hz

f' = 3.12 kHz

6 0

3 years ago