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2 years ago

• A plastic bag filled with air has a volume of

Physics

1 answer:

ratelena [41]2 years ago

8 0

Answer:

The change in the mass of box = 0.01 kg

Volume of air in the polythene bag = Volume of air in the rigid box

Therefore, Volume of air in the box = 0.008 m^3

Now, Density = Mass/ Volume

=> Density = 0.01 / 0.008 = 1.25 Kg / m^3

Explanation:

I looked it up

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What is the period of a wave with a frequency of 100 Hz and a wavelength of 2.0 m

spin [16.1K]

The answer for the following answer is answered below.

Therefore the time period of the wave is 0.01 seconds.
Therefore the option for the answer is "B".

Explanation:

Frequency (f):

The number of waves that pass a fixed place in a given amount of time.

The SI unit of frequency is Hertz (Hz)

Time period (T):

The time taken for one complete cycle of vibration to pass a given point.

The SI unit of time period is seconds (s)

Given:

frequency (f) = 100 Hz

wavelength (λ) = 2.0 m

To calculate:

Time period (T)

We know;

According to the formula;

f = $\frac{1}{T}$

Where,

f represents the frequency

T represents the time period

from the formula;

T = $\frac{1}{f}$

T = $\frac{1}{100}$

T = 0.01 seconds

Therefore the time period of the wave is 0.01 seconds.

5 0

2 years ago

Read 2 more answers

Make the following conversion. 120 mL = _____ cm³ 12.0 1200 120 1.20

omeli [17]

120 is your answer. 120 mL = 120 cm^3

7 0

3 years ago

Read 2 more answers

Hii please help i’ll give brainliest if you give a correct answer please

Diano4ka-milaya [45]

Answer:

Explanation:

6 0

2 years ago

a man applies a force of 100n to a rock for 60 seconds but the rock does not move what is the amount of work done by the man on

Phoenix [80]

0 (zero) work done.

This is because work can be calculated by:

Work = Force × Distance

The force is 100 N and since the rock didn't move the distance is zero and so:

Work = 100 × 0 = 0 J

8 0

3 years ago

A proton traveling along the x-axis enters a region at x = 0 where the x-component of the electric field is given by E = Ao/x1/2

storchak [24]

.Answer:

The value of the work done is $\bf{ 5.29 qA_{0}}$ .

Explanation:

When a charged particle having charge $q$ is moving through an electric field $E$ , the net force ( $F$ ) on the charge is

$F = qE~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(1)$

and the work done ( $W$ ) by the particle is

$W = \int\limits^x_0 {F} \, dx ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(2)$

Given, $E = \dfrac{A_{0}}{x^{1/2}}$ .

Substitute the value of electric field in equation (1) and then substitute the result in equation (2).

$W &=& \int\limits^7_0 {q\dfrac{A_{0}}{x^{1/2}}} \, dx \\&=& qA_{0} \int\limits^7_0 {x^{-1/2}} \, dx \\&=& 2qA_{0}[x^{1/2}]_{0}^{7}\\&=& 5.29 qA_{0}$

7 0

3 years ago