Answer:
2.65m/s
Explanation:
Using the equation of motion:
v² = u²+2a∆S where
v is the final velocity
u is the initial velocity
∆S is the change in distance
a is the acceleration
Given
u = 0m/s
a = 9.8m/s²
∆S = 1.3-0.943
∆S = 0.357m
Substituting the given parameters into the formula
v² = 0²+2(9.8)(0.357)
v² = 0+6.9972
v² = 6.9972
v=√6.9972
v = 2.65m/s
Hence the velocity at which it hit the ground is 2.65m/s
Answer:
A push or pull exerted on an object
<h2>Answer</h2>
The force will be doubled.
<h2>Explanation</h2>
Using Newton Law II,
<h3>F = ma </h3>
So it can be seen in the formula that force is directly proportional to mass and acceleration.
if mass is doubled ---> force will be doubled, keeping acceleration constant.
Similarly,
if acceleration is doubled ---? force is will be doubled, keeping mass constant.
<em>It is assumed that there is no friction, the object is in the air with no air resistance.</em>
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