Answer:
the speed of the sound in the air is 343.3 m/s
Explanation:
The computation of the speed of the sound in the air is shown below:
As we know that
Speed = Distance ÷ time
So, here speed be 515 m
And, the time is 1.50 seconds
So, the speed of the sound is
= 515 m ÷ 1.50 seconds
= 343.3 m/s
hence, the speed of the sound in the air is 343.3 m/s
C) because you could get hurt if certain items fall in it and you are in water
Answer:3.95 m/s
Explanation:
Given
radius of circle 
Water will not spill if the centripetal acceleration is greater than acceleration due to gravity
i.e. 






<h3>
Answer:</h3>

<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Physics</u>
<u>Energy</u>
Elastic Potential Energy: 
- U is energy (in J)
- k is spring constant (in N/m)
- Δx is displacement from equilibrium (in m)
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
k = 7.50 N/m
Δx = 0.40 m
<u>Step 2: Find Potential Energy</u>
- Substitute in variables [Elastic Potential Energy]:

- Evaluate exponents:

- Multiply:

- Multiply:

Answer:
λ₂ = 357.3 nm
Explanation:
The expression for double-slit interference is
d sin θ = m λ constructive interference
d sin θ = (m + ½) λ destructive interference.
The initial data corresponds to a constructive interference, they indicate that we are in the fourth order (m = 4), let's look for the separation of the slits
d sin θ = m λ₁
now ask for destructive interference for m = 4
d sin θ = (m + ½) λ₂
we match these two expressions
m λ₁ = (m + ½) λ₂
λ₂ = ( m / m + ½) λλ₁
let's calculate
λ₂ =
λ₂ = 357.3 nm