Answer:
They are both forms of energy. One has to do with hearing and the other a little bit of light.
Explanation:
The wavelength
![\lambda](https://tex.z-dn.net/?f=%5Clambda)
of the wave is 160 m, and this is the distance between two consecutive crests. The boat is located at a crest of the wave, this means that the first trough is located 80 meters from the boat (because the distance between a crest and a trough is half the wavelength).
The speed of the wave is
![v=56 km/h = 15.6 m/s](https://tex.z-dn.net/?f=v%3D56%20km%2Fh%20%3D%2015.6%20m%2Fs)
so the time the boat takes to reach the first trough is
Calculate the magnitude of the linear momen- tum for each of the following cases a) a proton with mass 1.67 × 10-27 kg mov- ing with a velocity of 6 × 106 m/s. Answer in units of kg · m/s.
The efficiency of the first Carnot engine is
n1 = 1 - Th/T
The efficiency of the second Carnot engine is
n2 = 1 - T/Tc
The total efficiency of the engines put in series is
n = 1 - Th/Tc
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Let say the height of two balls from the ground is H
now we can use kinematics
![s = v_i * t + \frac{1}{2} at^2](https://tex.z-dn.net/?f=%20s%20%3D%20v_i%20%2A%20t%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20at%5E2)
now we have
![H = \frac{1}{2}gt^2](https://tex.z-dn.net/?f=H%20%3D%20%5Cfrac%7B1%7D%7B2%7Dgt%5E2)
![t = \sqrt{\frac{2H}{g}}](https://tex.z-dn.net/?f=t%20%3D%20%5Csqrt%7B%5Cfrac%7B2H%7D%7Bg%7D%7D)
now in the same time ball on the left will cover the horizontal distance between them
![v_x = \frac{d}{ t}[/tex[tex]v_x = \frac{3}{\sqrt{\frac{2H}{g}}}](https://tex.z-dn.net/?f=v_x%20%3D%20%5Cfrac%7Bd%7D%7B%20t%7D%5B%2Ftex%3C%2Fp%3E%3Cp%3E%5Btex%5Dv_x%20%3D%20%5Cfrac%7B3%7D%7B%5Csqrt%7B%5Cfrac%7B2H%7D%7Bg%7D%7D%7D)
<em>so above is the horizontal speed of the left ball</em>