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4 years ago

Electron groups could be considered which of the following?

Physics

1 answer:

PSYCHO15rus [73]4 years ago

3 0

Electron groups could be considered as Lone pair electrons and bonded pairs of electrons.

Answer: Option D & B

<u>Explanation:</u>

The two or more electrons can be bonded by single bond, double bond, covalent bond of electrons can simply be lone pair of electrons. Unshared pair of electrons are generally termed as lone pair of electrons in an atom which are generally present in the outermost shell of atoms. Hence electron groups can be determined by bonded pairs and lone pairs of electrons.

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A force of 10 N causes a spring to extend by 20 mm. Find: a) the spring constant of the spring in N/m

Mars2501 [29]

Answer:

formula used K=F/∆l

∆l is the elongation of the spring

F=10N
∆l=20mm===> 0.02m
K=10N divided 0.02m= 500N/m

6 0

3 years ago

Find the net gravitational force fnet acting on the earth in the sun-earth-moon system during the new moon (when the moon is loc

Lina20 [59]

After thorough researching, the net gravitational force Fnet acting on the earth in the sun-earth-moon system during the new moon and when the moon is located directly between the earth and the sun is 3.50x10^22 N. The correct answer to the following given statement above is 3.50x10^22 N.

8 0

4 years ago

Read 2 more answers

You throw a ball with a speed of 25.0 m/s at an angle of 40.0â—¦ above the horizontal directly toward a wall. The wall is 22.0 m

Alina [70]

The ball takes about 1.15 seconds to reach the wall

<h3>Further explanation</h3>

Acceleration is rate of change of velocity.

$\large {\boxed {a = \frac{v - u}{t} } }$

$\large {\boxed {d = \frac{v + u}{2}~t } }$

<em>a = acceleration ( m/s² )</em>

<em>v = final velocity ( m/s )</em>

<em>u = initial velocity ( m/s )</em>

<em>t = time taken ( s )</em>

<em>d = distance ( m )</em>

Let us now tackle the problem!

This problem is about Projectile Motion

<u>Given:</u>

initial speed = u = 25 m/s

angle of speed = θ = 40.0°

horizontal distance = x = 22.0 m

<u>Unknown:</u>

time taken by the ball = t = ?

<u>Solution:</u>

<em>We will use this following formula to find the time taken by the ball to reach the wall:</em>

$x = u_x t$

$x = u \cos \theta ~t$

$22 = 25 \cos 40^o ~t$

$t = 22 \div ( 25 \cos 40^o )$

$t \approx 1.15 \texttt { seconds}$

$\texttt{ }$

<h2>Conclusion :</h2>

The ball takes about 1.15 seconds to reach the wall

$\texttt{ }$

<h3>Learn more</h3>

Velocity of Runner : brainly.com/question/3813437
Kinetic Energy : brainly.com/question/692781
Acceleration : brainly.com/question/2283922
The Speed of Car : brainly.com/question/568302

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Projectile , Motion , Horizontal , Vertical , Release , Point , Ball , Wall

7 0

3 years ago

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Which object has the greatest amount of kinetic energy?

EleoNora [17]

I think that the answer is A

4 0

4 years ago

A 25 N force at 60° is required to set a crate into motion on a floor. What is the value of the static friction?

True [87]

The normal force of the force given is calculated through the equation,

Fn = F(sin θ)
where Fn is the normal force, F is the force, and θ is the angle.

Fn = (25 N)(sin 60°) = 21.65 N

The x-component of the force applied is,
Fx = (25 N)(cos 60°) = 12.5 N

The value of the coefficient of static friction is calculated through the equation,
F = μFn
μ = Fx / Fn = 12.5 N / 21.65 N = 0.577

3 0

3 years ago