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krek1111 [17]
3 years ago
13

Early man removed salt from sea water by ____________.

Physics
1 answer:
Contact [7]3 years ago
5 0
Early man removed salt from sea water by evaporation.
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2.5: Một người nặng 72kg ngồi trên sàn treo nặng 12kg như hình vẽ. Hỏi người đó
Ivahew [28]

Answer:

english

Explanation:

5 0
3 years ago
Which one of the following temperatures is equal to 5°C?
natali 33 [55]

Answer : The correct option is, (D) 278 K

Explanation :

We are given temperature 5^oC.

Now the conversion factor used for the temperature is,

K=^oC+273

where, K is kelvin and ^oC is Celsius.

Now put the value of temperature, we get

K=5^oC+273=278K

Therefore, the temperature 278 K is equal to the 5^oC


7 0
3 years ago
Imagine you had a bar of gold and decided to cut in half. You repeated this process until eventually you could no longer cut the
nydimaria [60]

This would prove that gold is an <em>element</em>.  No matter how far down you
examine it, you never find any particles of anything except gold.

An example of a different case is salt. 
-- Imagine you had a block of salt and decided to cut it in half.
-- If you repeated this process, then eventually, at some point, you'd have
a tiny particle of salt in front of you, just like before.  BUT ...
-- Just as you were getting ready to cut this one in half, you'd notice that this
particle of salt is different.  It's one atom of sodium stuck to one atom of chlorine,
and if you cut it in half, you would not have ANY salt.   <span />

This would prove that salt is a <em><u>compound</u></em>, made of atoms of two or more elements.

3 0
4 years ago
Read 2 more answers
A basketball is shot at 14.0 m/s at a 65.0 degree angle. What is the magnitude only (no direction) of the velocity of the ball 2
Alex787 [66]

Answer:

10.4 m/s

Explanation:

I just know it's right!

8 0
3 years ago
a 10 uF capacitpr is connected to a 12 V battery till its fully charged. it is then disconnected and to an uncharged 20 uF capac
likoan [24]

Answer:

Explanation:

The charge on 10μF capacitor =  10 x 12 x 10⁻⁶ = 120 μC

when it is connected with 20μF capacitor both acquires common potential whose value is

= 120 x 10⁻⁶ /( 10 +20) x 10⁻⁶ = 4 V.

Energy stored in 20μF capacitor =1/2 x 20 x 10⁻⁶ x 4 x 4 = 160 x 10⁻⁶ J.

6 0
3 years ago
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