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3 years ago

An atom’s emission of light with a specific amount of energy confirms that

Physics

2 answers:

Vlad1618 [11]3 years ago

6 0

The answer is...

B-electrons emit and absorb energy based on their position around the nucleus.

I just took the test

laila [671]3 years ago

3 0

An atom’s emission of light with a specific amount of energy confirms that electrons emit and absorb energy based on their position around the nucleus.

The light emitted from an electron is a result of the electron's quantum jumps/leaps ( atomic electron transitions ) to and from different energy levels.

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A metal rod of length 2.0 m is moved at 6.0 m/s in a direction perpendicular to its length. A 5.0 mT magnetic field is perpendic

Lerok [7]

Answer:

<h2>The potential difference is 60mV</h2>

Explanation:

This problem bothers on application of the expression for motion emf which is expressed as

$E= Blv$

where B= magnetic field in Tesla

l= length of the conductor

v= speed of conductor

Given data

l= 2 meters

v= 6 m/s

B= 5 Tesla

Applying the formula we have

$E=5*2*6= 60mV$

7 0

3 years ago

A particle with charge 7.76×10^(−8)C is moving in a region where there is a uniform 0.700 T magnetic field in the +x-direction.

kodGreya [7K]

Answer:

The z-component of the force is $\= F_z = 0.00141 \ N$

Explanation:

From the question we are told that

The charge on the particle is $q = 7.76 *0^{-8} \ C$

The magnitude of the magnetic field is $B = 0.700\r i \ T$

The velocity of the particle toward the x-direction is $v_x = -1.68*10^{4}\r i \ m/s$

The velocity of the particle toward the y-direction is

$v_y = -2.61*10^{4}\ \r j \ m/s$

The velocity of the particle toward the z-direction is

$v_y = -5.85*10^{4}\ \r k \ m/s$

Generally the force on this particle is mathematically represented as

$\= F = q (\= v X \= B )$

So we have

$\= F = q ( v_x \r i + v_y \r j + v_z \r k ) \ \ X \ ( \= B i)$

$\= F = q (v_y B(-\r k) + v_z B\r j)$

substituting values

$\= F = (7.7 *10^{-8})([ (-2.61*10^{4}) (0.700)](-\r z) + [(5.58*10^{4}) (0.700)]\r y)$

$\= F= 0.00303\ \r j +0.00141\ \r k$

So the z-component of the force is $\= F_z = 0.00141 \ N$

Note : The cross-multiplication template of unit vectors is shown on the first uploaded image ( From Wikibooks ).

7 0

3 years ago

Which option is a force: A. velocity B. acceleration C. mass D. weight

ehidna [41]

Answer:

Explanation:

Weight and force have same derived units

8 0

3 years ago

If cake baking is compared to protein synthesis, what genetic structure would be analogous to the flour, sugar, and eggs?

galina1969 [7]

Mrnmrnamrnamrnamrnamrnamrnamrnamrnamrnamrna

7 0

3 years ago

The center-seeking change in velocity of an object moving in a circle is:

NeTakaya

The center-seeking change in velocity of an object moving in a circle is the centripetal acceleration.

So, by Newton's laws, we know that an object moving with a given velocity will remain in constant motion with a constant velocity until we apply an acceleration.

So we define acceleration as the rate of change of the velocity, also remember that velocity is a vector (has magnitude and direction), so, if there is a change the direction of the velocity, we have an acceleration that causes that.

In circular motion, the velocity vector is always perpendicular to the radius of the circle, and it can only be possible if the velocity direction is changing constantly. This will happen because of something called centripetal acceleration.

This acceleration points radially inwards (to the center of the circle) so is also perpendicular to the velocity of the moving object, and this is what causes the constant change in the direction of the velocity of the moving object.

Just to give an example, if you have a string with a mass on one end, and with your hand, you rotate the mass (from the string), the tension of the string would be the centripetal acceleration.

If you want to learn more about circular motion, you can read:

brainly.com/question/2285236

5 0

3 years ago

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