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postnew [5]
3 years ago
12

Find the kinetic energy of a 0.1-kilogram toy truck moving at the speed of 1.1 meters per second.

Physics
1 answer:
ZanzabumX [31]3 years ago
7 0

Answer:

0.061 J

Explanation:

The kinetic energy of an object is given by

K=\frac{1}{2}mv^2

where

m is the mass of the object

v is its speed

For the toy truck in the problem, we have

m = 0.1 kg is its mass

v = 1.1 m/s is its speed

Putting the numbers into the equation, we find

K=\frac{1}{2}(0.1 kg)(1.1 m/s)^2=0.061 J

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A volcanic eruption throws a boulder that lands 1.00 km horizontally from the crater. If the volcanic rocks were launched at an
Juliette [100K]

Answer:

a)  v₀ = 69.29 m / s , b)  t = 18.84 s

Explanation:

a) For this exercise we will use the projectile launch equations

          x = v₀ₓ t

          y = y₀ + v_{oy} t - ½ g t²

Let's fix our reference system on the volcano, so the horizontal distance x = 1 km = 1000 m and the vertical distance y = -900 m, the initial height of the crater is I = 0 m. Let's replace to find the speeds

         v_{oy} = v₀ sin θ

         v₀ₓ = v₀ cos θ

         y = v₀ sin θ (x / v₀ cos θ) - ½ g (x / v₀ cos θ)2

         y = x tan θ - ½ g x² / v₀² sec² θ

         ½ g x² sec² θ / v₀² = x tan θ - y

         v₀² = ½ g x² sec² θ / (x tan θ –y)

 

Let's calculate

           v₀² = ½ 9.8 1000² sec² 40 / (1000 tan 40 - (-900))

           v₀ = √ (8.35 10⁶ / 1,739 10³)

           v₀ = 69.29 m / s

    b) Flight time

           x = v₀ₓ t

           t = x / v₀ cos θ

           t = 1000 / 69.29 cos 40

           t = 18.84 s

7 0
3 years ago
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