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I am Lyosha [343]
3 years ago
14

You mix 145 grams of water with 200 grams of ethanol to make a solution. What is the solute and what is the solvent?

Chemistry
1 answer:
pentagon [3]3 years ago
6 0

The greater amount is the solvent and the lesser amount is the solute.

Hence ethanol(200g) which is the greater amount is the solvent here.

And water (145g) which is lesser is the solute here.

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Suppose you wanted to dissolve 40.0 g NaOH in enough H2O to make 6.00 dm3 of solution
dezoksy [38]

Molarity of solution = 1.6 M

<h3>Further explanation</h3>

Given

40 g NaOH

6 L solution

Required

Steps to solve the problem of molarity

Solution

No additional information about the question.

If you want to make the solution above, then we just need to put the existing NaOH (40 g) into 6 L of water, then do the stirring (in a warm temperature above the hot plate will speed up the NaOH dissolving process)

But if you want to know the molarity of a solution, then

  • 1. we calculate the moles of NaOH

\tt mol=\dfrac{mass}{MW}

MW(molecular weight) of NaOH=

Ar Na+ Ar O + Ar H

23 + 16 + 1 = 40 g/mol

so mol NaOH :

\tt mol=\dfrac{40~g}{40~g/mol}=1~mol

  • 2. Molarity(M)

\tt M=\dfrac{n}{V}\\\\M=\dfrac{1}{6}\\\\M=0.16

5 0
3 years ago
If 9 moles of nitrogen gas and 9 moles of hydrogen
Luda [366]

Answer:

dnfberbgiieur

Explanation:

4 0
4 years ago
A compound has the molecular formula C3H8. Which class of organic compounds does it belong to?
Serhud [2]

Answer & Explanation:

  • The compound is considered as hydrocarbon because it contains only carbon and hydrogen.
  • Also, it is alkane compound because all the bonds are saturated (single bonds).
  • CH₃CH₂CH₃ "propane".
7 0
3 years ago
Which acid was used in the titration curve below?<br><br><br> HCl<br> H2 S O4<br> HNO3<br> H3PO4
pychu [463]

HNO3

Explanation:

hydrochloric acid (HCl), sulfuric acid (H 2start subscript, 2, end subscriptSO 4start subscript, 4, end subscript), nitric acid (HNO 3start

3 0
3 years ago
Pls help :)
prisoha [69]

Answer:

0.484 mole

Explanation:

1 mole of glucose reacts with 6 moles of O2, producing :

6 moles of CO2

6 moles of H2O

678 kcal

Using rule of three you have:

1 mole of glucose -> 678 kcal

x mole of glucose -> 328 kcal

x = 328/678 * 1 =0.484 mole

6 0
4 years ago
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