Molarity of solution = 1.6 M
<h3>Further explanation</h3>
Given
40 g NaOH
6 L solution
Required
Steps to solve the problem of molarity
Solution
No additional information about the question.
If you want to make the solution above, then we just need to put the existing NaOH (40 g) into 6 L of water, then do the stirring (in a warm temperature above the hot plate will speed up the NaOH dissolving process)
But if you want to know the molarity of a solution, then
- 1. we calculate the moles of NaOH

MW(molecular weight) of NaOH=
Ar Na+ Ar O + Ar H
23 + 16 + 1 = 40 g/mol
so mol NaOH :


HNO3
Explanation:
hydrochloric acid (HCl), sulfuric acid (H 2start subscript, 2, end subscriptSO 4start subscript, 4, end subscript), nitric acid (HNO 3start
Answer:
0.484 mole
Explanation:
1 mole of glucose reacts with 6 moles of O2, producing :
6 moles of CO2
6 moles of H2O
678 kcal
Using rule of three you have:
1 mole of glucose -> 678 kcal
x mole of glucose -> 328 kcal
x = 328/678 * 1 =0.484 mole