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Mrrafil [7]
3 years ago
12

The intersection angle of a 3 degree curve is 45.2 degrees. What is the length of the curve? of Select one: O a. 455 m O b.573 m

C. 452 m O d. 25.9 km
Chemistry
1 answer:
ValentinkaMS [17]3 years ago
7 0

Explanation:

Relation between length of a curve and angle is as follows.

               l = R \times \Theta

where,   R = radius of curve

         \Theta = angle in radians

Also,     l = R \times \Theta \times \frac{\pi}{180}  .......... (1)

If curve has a degree of curvature D_{a} for standard length s, then

               R = \frac{s}{D_{a}} \times \frac{180}{\pi}   ........... (2)

Now, substitute the value of R from equation (2) into equation (1) as follows.

               l = \frac{s \times \Theta}{D_{a}}  

If s = 30 m, then calculate the value of l as follows.

                 l = \frac{s \times \Theta}{D_{a}}  

                   = 30 \times \frac{45.2}{3}              

                   = 452 m

thus, we can conclude that the length of the curve is 452 m.

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B) cobalt  - 3

C) sulfur   - 2

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Explanation:

Hund's rule of maximum multiplicity:-

Firstly, every orbital which is present in the sublevel is singly occupied and then the orbital is doubly occupied.  

(A) Carbon.

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Thus, 2s orbital is fully filled and p orbital can singly filled 3 electrons. Thus, Carbon has 2 singly occupied orbitals.

(B) Cobalt.

The electronic configuration is -  

1s^22s^22p^63s^23p^63d^{7}4s^2

Thus, 4s orbital is fully filled and d orbital can singly filled 5 electrons. Thus, 4 electrons will be paired in 2 orbitals and 3 orbitals will be singly filled in cobalt.

(C) Sulfur.

The electronic configuration is -  

1s^22s^22p^63s^23p^4

Thus, 3s orbital is fully filled and p orbital can singly filled 3 electrons. Thus, 2 electrons will be paired in 1 orbital and 2 orbitals will be singly filled in sulfur.

D) fluorine

The electronic configuration is -  

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Thus, 2s orbital is fully filled and p orbital can singly filled 3 electrons. Thus, 4 electrons will be paired in 2 orbitals and 1 orbital will be singly filled in fluorine.

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1s^22s^22p^63s^23p^63d^{2}4s^2

Thus, 4s orbital is fully filled and d orbital can singly filled 5 electrons. Thus, 2 orbitals will be singly filled in titanium.

F) Germanium

The electronic configuration is -  

1s^22s^22p^63s^23p^63d^{10}4s^24p^2

Thus, 4s, 3d orbitals are fully filled and p orbital can singly filled 3 electrons. Thus, Germanium has 2 singly occupied orbitals.

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The reaction here is the formation of iodine from MnO2 and KI in the presence of dropwise H2SO4.

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