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STOICHIOMETRY AND PERCENT PURITY
1 answer:
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The molarity of the stock solution is 1.25 M.
<u>Explanation:</u>
We have to find the molarity of the stock solution using the law of volumetric analysis as,
V1M1 = V2M2
V1 = 150 ml
M1 = 0.5 M
V2 = 60 ml
M2 = ?
The above equation can be rearranged to get M2 as,
M2 =
Plugin the values as,
M2 =
= 1.25 M
So the molarity of the stock solution is 1.25 M.
<u>Answer:</u> The heat required will be 58.604 kJ.
<u>Explanation: </u>
To calculate the amount of heat required, we use the formula:
Q= heat gained or absorbed = ? J
m = mass of the substance = 100 g
c = heat capacity of water = 4.186 J/g ° C
Putting values in above equation, we get:
Q = 58604 Joules = 58.604 kJ (Conversion factor: 1 kJ = 1000J)
Thus, heat released by 100 grams of ice is 58.604kJ.