What is the mass of sulfuric acid in 50.0 mL of a 6.00 M solution?

Chemistry

1 answer:

Evgesh-ka [11]3 years ago

6 0

Answer:

The answer to your question is 29.4 grams of H₂SO₄

Explanation:

Data

mass of sulfuric acid

volume = 50 ml

Molarity = 6 M

Process

1.- Write the formula of Molarity

Molarity = moles / volume

-Solve for moles

moles = Molarity x volume

-Substitution

moles = 6 x 0.05

-result

moles = 0.3

2.- Calculate the molar mass of Sulfuric acid

H₂SO₄ = (1 x 2) + (32 x 1) + (16 x 4) = 2 + 32 + 64 = 98 g

3.- Calculate the mass in the solution

98 g of H₂SO₄ ---------------- 1 mol

x ----------------- 0.3 moles

x = (0.3 x 98) / 1

x = 29.4 grams of H₂SO₄

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