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Luda [366]
3 years ago
11

What is the mass of sulfuric acid in 50.0 mL of a 6.00 M solution?

Chemistry
1 answer:
Evgesh-ka [11]3 years ago
6 0

Answer:

The answer to your question is 29.4 grams of H₂SO₄

Explanation:

Data

mass of sulfuric acid

volume = 50 ml

Molarity = 6 M

Process

1.- Write the formula of Molarity

Molarity = moles / volume

-Solve for moles

moles = Molarity x volume

-Substitution

moles = 6 x 0.05

-result

moles = 0.3

2.- Calculate the molar mass of Sulfuric acid

H₂SO₄ = (1 x 2) + (32 x 1) + (16 x 4) = 2 + 32 + 64 = 98 g

3.- Calculate the mass in the solution

                 98 g of H₂SO₄ ---------------- 1 mol

                    x                   ----------------- 0.3 moles

                            x = (0.3 x 98) / 1

                            x = 29.4 grams of H₂SO₄

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\large \boxed{\text{4.63 atm}}

Explanation:

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(b) Calculate the new pressure

\begin{array}{rcl}\dfrac{p_{1}V_{1}}{n_{1} T_{1}} & = & \dfrac{p_{2}V_{2}}{n_{2} T_{2}}\\\\\dfrac{\text{2.02 atm}\times \text{736 mL}}{n _{1}\times \text{274.15 K}} & = &\dfrac{p_{2}\times \text{416 mL}}{n _{1}\times \text{355.15 K}}\\\\\text{5.423 atm} & = &1.171{p_{2}}\\p_{2} & = & \dfrac{\text{5.423 atm}}{1.171}\\\\ & = & \textbf{4.63 atm} \\\end{array}\\\text{The  new pressure will be $\large \boxed{\textbf{4.63 atm}}$}}

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