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Luda [366]
3 years ago
11

What is the mass of sulfuric acid in 50.0 mL of a 6.00 M solution?

Chemistry
1 answer:
Evgesh-ka [11]3 years ago
6 0

Answer:

The answer to your question is 29.4 grams of H₂SO₄

Explanation:

Data

mass of sulfuric acid

volume = 50 ml

Molarity = 6 M

Process

1.- Write the formula of Molarity

Molarity = moles / volume

-Solve for moles

moles = Molarity x volume

-Substitution

moles = 6 x 0.05

-result

moles = 0.3

2.- Calculate the molar mass of Sulfuric acid

H₂SO₄ = (1 x 2) + (32 x 1) + (16 x 4) = 2 + 32 + 64 = 98 g

3.- Calculate the mass in the solution

                 98 g of H₂SO₄ ---------------- 1 mol

                    x                   ----------------- 0.3 moles

                            x = (0.3 x 98) / 1

                            x = 29.4 grams of H₂SO₄

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Explanation:

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Thickness of a Astroturf with which soccer field is to be covered = h

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V=328.0992 ft\times 253 ft\times 0.041665 ft=3,458.574 ft^3

Mass of the Astroturf = m

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1 oz = 0.0283495 kg

m=646,743.35 oz=646,743.35\times 0.0283495 kg=18,335.13 kg

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