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Luda [366]
3 years ago
11

What is the mass of sulfuric acid in 50.0 mL of a 6.00 M solution?

Chemistry
1 answer:
Evgesh-ka [11]3 years ago
6 0

Answer:

The answer to your question is 29.4 grams of H₂SO₄

Explanation:

Data

mass of sulfuric acid

volume = 50 ml

Molarity = 6 M

Process

1.- Write the formula of Molarity

Molarity = moles / volume

-Solve for moles

moles = Molarity x volume

-Substitution

moles = 6 x 0.05

-result

moles = 0.3

2.- Calculate the molar mass of Sulfuric acid

H₂SO₄ = (1 x 2) + (32 x 1) + (16 x 4) = 2 + 32 + 64 = 98 g

3.- Calculate the mass in the solution

                 98 g of H₂SO₄ ---------------- 1 mol

                    x                   ----------------- 0.3 moles

                            x = (0.3 x 98) / 1

                            x = 29.4 grams of H₂SO₄

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valentinak56 [21]

Given :

Number of molecules of hydrogen peroxide, N = 4.5 × 10²².

To Find :

The mass of given molecules of hydrogen peroxide.

Solution :

We know, 1 mole of every compound contains Nₐ = 6.022 × 10²³ molecules.

So, number of moles of hydrogen peroxide is :

n = \dfrac{N}{N_a}\\\\n = \dfrac{4.5\times 10^{22}}{6.022\times 10^{23}}\\\\n = 0.0747 \ moles

Now, mass of hydrogen peroxide is given as :

m = n × M.M

m = 0.0747 × 34 grams

m = 2.54 grams

Hence, this is the required solution.

6 0
3 years ago
Which of the following is most likely to dissolve in NH3? A) CO2 B) CH4 C) H2S D) BH3
dem82 [27]

Answer:

C) H2S

Explanation:

In chemistry, the dissolution of one substance in another is dependent on the magnitude of intermolecular interaction between the two substances.  Hence, if two substances do not interact in one way or the other, then one can not dissolve the other.

Let us consider the fact that NH3 is a polar molecule and it is a general principle that like dissolves like. Hence, only H2S which is also a polar molecule can effectively interact with  NH3 due to dipole-dipole interaction between the two molecules.

Also, ammonia reacts with hydrogen sulphide as follows;

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5 0
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Answer:

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What is the wavelength of light emitted when the electron in a hydrogen atom undergoes transition from an energy level with n =
Lady bird [3.3K]

Answer:

4.86\times10^{-7}\ \text{m}

Explanation:

R = Rydberg constant = 1.09677583\times 10^7\ \text{m}^{-1}

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n_2 = Principal quantum number of an energy level for the atomic electron transition = 4

Wavelength is given by the Rydberg formula

\lambda^{-1}=R\left(\dfrac{1}{n_1^2}-\dfrac{1}{n_2^2}\right)\\\Rightarrow \lambda^{-1}=1.09677583\times 10^7\left(\dfrac{1}{2^2}-\dfrac{1}{4^2}\right)\\\Rightarrow \lambda=\left(1.09677583\times 10^7\left(\dfrac{1}{2^2}-\dfrac{1}{4^2}\right)\right)^{-1}\\\Rightarrow \lambda=4.86\times10^{-7}\ \text{m}

The wavelength of the light emitted is 4.86\times10^{-7}\ \text{m}.

6 0
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