We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.
First, we need to determine the required moles of CaCl₂. We have 500 mL (0.500 L) of a 0.360 M solution (0.360 moles of CaCl₂ per liter of solution).
Then, we will convert 0.180 moles to grams using the molar mass of CaCl₂ (110.98 g/mol).
To prepare the solution, we weigh 20.0 g of CaCl₂ and add it to a beaker with enough distilled water to dissolve it. We stir it, heat it if necessary, and when we have a solution, we transfer it to a 500 mL flask and complete it to the mark with distilled water.
We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.
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Answer:
Explanation:
q= mc theta
where,
Q = heat gained
m = mass of the substance = 670g
c = heat capacity of water= 4.1 J/g°C
theta =Change in temperature=(
66-25.7)
Now put all the given values in the above formula, we get the amount of heat needed.
q= mctheta
q=670*4.1*(66-25.7)
=670*4.1*40.3
=110704.1
Answer:
The thermal energy (heat) needed, to raise the temperature of oil of mass 'm' kilogram and specific heat capacity 'c' from 20°C to 180°C is 160·m·c joules
Explanation:
The heat capacity, 'C', of a substance is the heat change, ΔQ, required by a given mass, 'm', of the substance to produce a unit temperature change, ΔT
∴ C = ΔQ/ΔT
ΔQ = C × ΔT
C = m × c
Where;
c = The specific heat capacity
ΔT = The temperature change = T₂ - T₁
∴ ΔQ = m × c × ΔT
Therefore, the thermal energy (heat) needed, ΔQ, to raise the temperature of oil of mass 'm' kilogram and specific heat capacity, 'c' from 20°C to 180°C is given as follows;
ΔQ = m × c × (180° - 20°) = 160° × m·c
ΔQ = 160·m·c joules
Answer : Option A) the arrangement of bonded atoms.
Explanation : A structural formula of certain molecule depicts the way the atoms are arranged in that particular molecule in any polyatomic species. It helps in deciding the chemical properties of that polyatomic molecule.
Answer:
A) 
B) 0.025 mol (SCN)₂
C) 2 mol (SCN)₂
D) 
E) 3.5504 mol H₂SO₄
Explanation:
2NaSCN +2H₂SO₄ + MnO₂ → (SCN)₂ + 2H₂O + MnSO₄ + Na₂SO₄
A) A conversion factor could be , as it has the units that we want to <u>convert to in the numerator</u>, and the units that we want to <u>convert from in the denominator</u>.
B) 0.05 mol NaSCN * = 0.025 mol (SCN)₂
C) With 4 moles of NaSCN and 3 moles of MnSO₄, the<em> reactant </em>is NaSCN so we use that value to calculate the moles of product formed:
4 mol NaSCN * = 2 mol (SCN)₂
D)
E) 1.7752 mol MnSO₄ * 
= 3.5504 mol H₂SO₄
