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earnstyle [38]
3 years ago
7

Water has a boiling point of 100.0°C and a Kb of 0.512°C/m. What is the boiling

Chemistry
1 answer:
Neko [114]3 years ago
3 0

Answer:

104.352°C

Explanation:

Data Given:

Boiling point of water = 100.0°C

Kb (boiling point constant = 0.512°C/m

Concentration of the Mg₃(PO₄)₂ = 8.5 m

Solution:

Formula Used to find out boiling point

               ΔTb = m.Kb . . . . . . (1)

where

               ΔTb = boiling point of solution - boiling point of water

So,

we can write equation 1 as under

               ΔTb = Tb (Solution) -Tb (water)

As we have to find out boiling point so rearrange the above equation

              Tb (Solution)  = m.Kb + Tb (water) . . . . . . . (2)

Put values in Equation 2

            Tb (Solution)  = (8.5 m x 0.512°C/m ) + 100.0°C

            Tb (Solution)  = 4.352 + 100.0°C

            Tb (Solution)  = 104.352°C

so the boiling point of Mg₃(PO₄)₂  8.5 m solution =  104.352°C

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BaLLatris [955]

This is an incomplete question, here is a complete question.

The balanced chemical reaction is:

6XO_3+8BrZ_3\rightarrow 6XZ_4+4Br_2+9O_2

In another experiment, if 80 XO_3 molecules react with 104 BrZ_3 molecules. How many Br_2 molecules will be produced which reactant will be used up in the reaction.

Answer : The number of molecules of Br_2  will be, 52 molecules and BrZ_3 reactant will be used up in the reaction because it is a limiting reagent and it limits the formation of product.

Explanation :

The balanced chemical reaction is:

6XO_3+8BrZ_3\rightarrow 6XZ_4+4Br_2+9O_2

First we have to determine the limiting reagent.

From the balanced reaction we conclude that,

As, 8 molecules of BrZ_3 react with 6 molecule of XO_3

So, 104 molecules of BrZ_3 react with \frac{104}{8}\times 6=78 molecule of XO_3

From this we conclude that, XO_3 is an excess reagent because the given moles are greater than the required moles and BrZ_3 is a limiting reagent and it limits the formation of product.

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From the reaction, we conclude that

As, 8 molecules of BrZ_3 react to give 4 molecules of Br_2

So, 104 molecules of BrZ_3 react to give \frac{104}{8}\times 4=52 molecules of Br_2

Hence, the number of molecules of Br_2  will be, 52 molecules and BrZ_3 reactant will be used up in the reaction because it is a limiting reagent and it limits the formation of product.

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yanalaym [24]

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Explanation:

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2 years ago
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Answer:

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igor_vitrenko [27]

Answer:

C2H2O4

Explanation:

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O = 100 - ( 26.86 + 2.239) = 70.901%

We then proceed to divide by their atomic masses. Atomic mass of carbon is 12 a.m.u , H = 1 a.m.u , O = 16 a.m.u

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Explanation: Sup. Hope dis helps u bro

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