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Ivahew [28]
3 years ago
9

The isotope 106 46Pd (106 on top and 46 on bottom)

Chemistry
1 answer:
vazorg [7]3 years ago
7 0

Answer:

4. 60 neutrons.

Explanation:

The given isotopes;

         ¹⁰⁶₄₆Pd

In this isotope, we can deduce that the mass number is the superscript and the atomic number is the subscript;

     Mass number  = 106

     Atomic number  = 46

Mass number is the number of protons and neutrons in an atom;

       Mass number = Protons + neutrons

Atomic number is the number of protons

   

So,  Number of protons  = 46

Number of neutrons  = Mass number  - Atomic number

                                    = 106  - 46

                                     = 60

Number of neutrons  = 60

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Answer:

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Which example is an endothermic process
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Answer:

Endothermic reactions is the result of heat being absorbed.

Explanation:

Melting ice cubes. Melting solid salts. Evaporating liquid water. Converting frost to water vapor (melting, boiling, and evaporation, in general, are endothermic processes.

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2 years ago
What is an isotope? list the isotopes of hydrogen in order from lighter to heavier. which is the most common among them?
malfutka [58]
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6 0
3 years ago
Given the following thermodynamic data, calculate the lattice energy of LiCl:
tiny-mole [99]

Answer:

\boxed{\text{-862 kJ/mol}}

Explanation:

One way to calculate the lattice energy is to use Hess's Law.

The lattice energy U is the energy released when the gaseous ions combine to form a solid ionic crystal:

Li⁺(g) + Cl⁻(g) ⟶ LiCl(s); U = ?

We must generate this reaction rom the equations given.

(1)  Li(s) + ½Cl₂ (g) ⟶ LiCl(s);      ΔHf°     = -409 kJ·mol⁻¹

(2) Li(s) ⟶ Li(g);                          ΔHsub =    161 kJ·mol⁻¹

(3) Cl₂(g) ⟶ 2Cl(g)                     BE        =   243 kJ·mol⁻¹

(4) Li(g) ⟶Li⁺(g) +e⁻                   IE₁         =   520 kJ·mol⁻¹

(5) Cl(g) + e⁻ ⟶ Cl⁻(g)                EA₁       =  -349 kJ·mol⁻¹

Now, we put these equations together to get the lattice energy.

                                                <u>E/kJ </u> 

(5) Li⁺(g) +e⁻ ⟶ Li(g)                520

(6) Li(g) ⟶ Li(s)                         -161

(7) Li(s) + ½Cl₂(g) ⟶ LiCl(s)     -409

(8) Cl(g) ⟶ ½Cl₂(g)                   -121.5

(9) Cl⁻(g) ⟶ Cl(g) + e⁻               <u>+349</u>

      Li⁺(g) +  Cl⁻(g) ⟶ LiCl(s)     -862

The lattice energy of LiCl is \boxed{\textbf{-862 kJ/mol}}.

3 0
3 years ago
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