Question

A plane flies 125 km/hr at 25 degrees north of east with a wind speed of 36 km/hr at 6 degrees south of east. What is the resulting velocity of the plane (in km/hr)?

Answer 1

Answer:

V = 156.85 Km/h

Explanation:

Speed of plane = 125 Km/h

angle of plane=  25° N of E

Speed of wind = 36 Km/h

angle of plane = 6° S of W

Horizontal component of the velocity

V_x = 125 cos 25° + 36 cos 6°

V_x = 149 Km/h

Vertical component of the velocity

V_y = 125 sin 25° - 36 sin 6°

V_y = 49 Km/h

Resultant of Velocity

$V = \sqrt{V_x^2 + V_y^2}$

$V = \sqrt{149^2 + 49^2}$

  V = 156.85 Km/h

the resulting velocity of the plane is equal to  V = 156.85 Km/h