<u>**Answer:**</u>** The amount of hex-3-ene used is 0.0711 moles and the percent yield of 3-hexanol is 59.56 %**

<u>**Explanation:**</u>

**To calculate the number of moles, we use the equation:**

** .....(1)**

Given mass of hex-3-ene = 5.84 g

Molar mass of hex-3-ene = 82.14 g/mol

**Putting values in equation 1, we get:**

**The chemical equation for the conversion of hex-3-ene to 3-hexanol follows:**

**By Stoichiometry of the reaction:**

1 mole of hex-3-ene produces 1 mole of 3-hexanol

So, 0.0711 moles of hex-3-ene will produce = of 3-hexanol

**Now, calculating the mass of 3-hexanol from equation 1, we get:**

Molar mass of 3-hexanol = 102.2 g/mol

Moles of 3-hexanol = 0.0711 moles

**Putting values in equation 1, we get:**

**To calculate the percentage yield of 3-hexanol, we use the equation:**

Experimental yield of 3-hexanol = 4.33 g

Theoretical yield of 3-hexanol = 7.27 g

**Putting values in above equation, we get:**

**Hence, the amount of hex-3-ene used is 0.0711 moles and the percent yield of 3-hexanol is 59.56 %**