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4 years ago

What is the molarity of a solution that is made by adding 57.3 g of MgO to 500.0 mL of solution?

Chemistry

1 answer:

kifflom [539]4 years ago

0 0

Answer:

2.843 M

Explanation:

Molarity = moles / volume

Milliliters to liters:

500 mL = .500 L

Grams to moles:

MgO molar mass = 16.00 + 24.31 = 40.31 g/mol

57.3 g x 1 mol / 40.31 g = 1.421 mol

Molarity:

1.421 mol / .500 L = 2.843 M

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Do valence electrons show a repeating or periodic pattern

PolarNik [594]

Yes

Explanation:

Valence electrons on the periodic table of elements shows a repeating or periodic pattern. There is a noticeable pattern that can be deduced from the valence electrons in the orbitals of atoms.

Valence electrons are the electrons in the outermost shell of an element

The periodic table arranges elements based on their atomic numbers. This number denotes the number of protons or electrons an atom contains.

The table is divided into groups which are the vertical columns into which elements are classified.
The horizontal rows are called periods.
A period begins with one valence electron and ends with an atom having complete outer shell structure of an inert gas.
Down a group the valence electron is the same. The group number denotes the number of valence electrons in a group. Group 1 has just one valence electron in their outermost shell.

Learn more:

Valence electrons brainly.com/question/12580690

Periodic table brainly.com/question/2014634

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8 0

3 years ago

Suppose 3.68g of zinc was allowed to react with hydrochloric acid to produce zinc chloride and hydrogen gas. How much zinc chlor

valentina_108 [34]

Answer:

Percent yield = 86.2%

Explanation:

Given data:

Mass of zinc = 3.68 g

Mass of zinc chloride = ?

Percent yield = ?

Actual yield = 7.12 g

Solution:

Chemical equation:

Zn + 2HCl → ZnCl₂ + H₂

Number of moles of zinc:

Number of moles = Mass /molar mass

Number of moles = 3.68 g / 65.38 g/mol

Number of moles = 0.06 mol

Now we will compare the moles of ZnCl₂ with zinc.

Zn : ZnCl₂

1 : 1

0.06 : 0.06

Theoretical yield of zinc chloride:

Mass of ZnCl₂ = moles × molar mass

Mass of ZnCl₂ = 0.06 mol × 136.286 g/mol

Mass of ZnCl₂ = 8.2 g

Percent yield:

Percent yield = actual yield / theoretical yield × 100

Percent yield = 7.12 g/ 8.2 g × 100

Percent yield = 86.2%

7 0

4 years ago

Hello can someone help me please and thanksss

Svetlanka [38]

the equation of the parabola is given as $y = 1/4 (x-6)^2 +1$ . D

<h3>How to find the parabola</h3>

Given the focus(6,2) and the directrix, y = 0

Use the formula

$\sqrt{(x-6)^{2} + (y-2)^{2} } }$ = (y - 0)

Find the square of both sides, square root is removed from the side with it and square added on the other side

$(x-6)^2 + (y-2)^2 = (y- 0)^{2}$

Expand the expression and bring all terms to one side

$x^{2} - 6x - 6x + 36 +y^{2} -2y- 2y +4$ = $y^{2} - 0$

Collect like terms

$x^{2} - 12x -4y + 40 = 0$

Make 'y' the subject of the formula

$4y = x^{2} - 12x + 40$

Divide through by 4 and substrate 4 from 40 to give a perfect quadratic equation

$y = 1/4 x^{2} - 12x + 36 + 4$

Divide factor by 4 to give 1

$y = 1/4( x^{2} -6x -6x +36) + 1$

Simplify the expanded quadratic equation

$y = x (x -6) - 6 (x- 6)$ , we have $(x - 6) ^2$

Then insert in place into previous equation

$y = 1/4 (x-6)^2 + 1$

Thus, the equation of the parabola is given as $y = 1/4 (x-6)^2 +1$

Learn more about a parabola here:

brainly.com/question/4061870

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5 0

2 years ago

What is the empirical formula? A compound is used to treat iron deficiency in people. It contains 36.76% iron, 21.11% sulfur, an

Mandarinka [93]

Answer: The empirical formula of the compound is $Fe_1S_1O_4$

Explanation:

Empirical formula is defined formula which is simplest integer ratio of number of atoms of different elements present in the compound.

Percentage of iron in a compound = 36.76 %

Percentage of sulfur in a compound = 21.11 %

Percentage of oxygen in a compound = 42.13 %

Consider in 100 g of the compound:

Mass of iron in 100 g of compound = 36.76 g

Mass of iron in 100 g of compound = 21.11 g

Mass of iron in 100 g of compound = 42.13 g

Now calculate the number of moles each element:

Moles of iron= $\frac{36.76 g}{55.84 g/mol}=0.658 mol$

Moles of sulfur= $\frac{21.11 g}{32.06 g/mol}=0.658 mol$

Moles of oxygen= $\frac{42.13 g}{16 g/mol}=2.633 mol$

Divide the moles of each element by the smallest number of moles to calculated the ratio of the elements to each other

For Iron element = $\frac{0.658 mol}{0.658 mol}=1$

For sulfur element = $\frac{0.658 mol}{0.658 mol}=1$

For oxygen element = $\frac{2.633 mol}{0.658 mol}=4.001\approx 4$

So, the empirical formula of the compound is $Fe_1S_1O_4$

4 0

3 years ago

Read 2 more answers

What elects have properties like iron

Elis [28]

Answer:

Cobalt and nickel are trace elements with properties similar to iron.

3 0

3 years ago