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Sever21 [200]
2 years ago
12

Rubbing alcohol is 70.% (v/v) isopropyl alcohol by volume. How many mL of isopropyl alcohol are in a 1 pint (473 mL) container?

Rubbing alcohol is 70.% (v/v) isopropyl alcohol by volume. How many mL of isopropyl alcohol are in a 1 pint (473 mL) container? 330 mL 470 mL 70. mL 680 mL 0.15 mL
Chemistry
1 answer:
katovenus [111]2 years ago
3 0

Answer:

helped

The number  of ml of isopropyl  alcohol  that are 1 pint (473 Ml)   is  331.1 Ml

  calculation

assume  that  the 1 pint  is in  a  container

  This implies  that the 1 pint (473 ml)  is  in 100 %  M/V

     what about 70 %(M/V)

that is  473 Ml  = 100 %

                  ?   =   70 %

by  cross  multiplication

   =  473 x70/100 = 331.1 Ml

Explanation:

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i don't need these solved I just need the steps to solve it and. what these problems in chemistry would be called so I can look
wolverine [178]

The answers are as follows,

1. 4.71 L,

2. 3.29 L,

3. 1634.6 torr

<u>Explanation:</u>

All the above problems can be sorted out using the Boyle's law represents the relationship between the volume and pressure.

It can be expressed as follows,

                      P1V1 = P2V2

Rearranging the above expression, we get,

                     $ V2 = \frac{P1V1}{V2}

1) The first case can be solved as,

     $V 2=\frac{921 \mathrm{mm} \mathrm{Hg} \times 3.89 \mathrm{L}}{760 \mathrm{mm} \mathrm{Hg}}=4.71 \mathrm{L}

2) The second case can be solved as,

       $V 2=\frac{25 L \times 600 \text { torr}}{4560 \text { torr}}=3.29 L

3) The third case can be solved as,

     $P 2=\frac{7.43 L \times 1100 \text { torr}}{5 L}=1634.6 \text { torr}

Thus the answers for all the three cases are found as,

1. 4.71 L,

2. 3.29 L,

3. 1634.6 torr respectively

6 0
2 years ago
Because of its high heat content, the most valuable type of coal is __________.
viva [34]
C.
Anthracite has the highest carbon compact and fewest impurities.
Also, the highest calorific of all types of coal except for graphite.
8 0
3 years ago
This reaction is sometimes used to inflate life rafts, weather balloons, and the like, where a simple, compact means of generati
tia_tia [17]

Answer: 10.2 grams

Explanation:

The balanced chemical reaction is :

CaH_2(s)+2H_2O(l)\rightarrow Ca(OH)_2(aq)+2H_2(g)

According to the ideal gas equation:

PV=nRT

P = Pressure of the gas = 740 torr =  0.97 atm    (760torr=1atm)

V= Volume of the gas = 12.0 L

T= Temperature of the gas = 19°C = 292 K    0^0C=273K

R= Gas constant = 0.0821 atmL/K mol

n= moles of gas

n=\frac{PV}{RT}=\frac{0.97\times 12.0}{0.0821\times 292}

n=0.48

According to stoichiometry:

2 moles of hydrogen are generated by = 1 mole of CaH_2

Thus 0.48 moles of hydrogen are generated by =\frac{1}{2}\times 0.48=0.24 moles of CaH_2

Mass of  CaH_2=moles\times {\text {Molar mass}}=0.24mol\times 42g/mol=10.2g

Thus 10.2 grams of CaH_2 are needed to generate 12.0 L of hydrogen gas if the pressure of hydrogen is 740. torr at 19°C

5 0
3 years ago
The following balanced equation shows the decomposition of ammonia (NH3) into nitrogen (N2) and hydrogen (H2). 2NH3 → N2 + 3H2 A
Triss [41]
The decomposition of ammonia is characterized by the following decomposition equation:
                                  2NH₃<span>   →   N</span>₂  <span> +   3H</span>₂   

The mole ratio of N₂  :  H₂  is  1  :  3

    If the number of moles of N₂  =  0.0351 mol
    Then the number of moles of H₂  =  0.0351 mol  × 3
                                                         = 0.1053 mol

The number of moles of hydrogen gas produced when 0.0351 mol of Nitrogen gas is produced after the decomposition of Ammonia is  0.105 mol (OPTION 3).

6 0
2 years ago
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alukav5142 [94]

Answer:

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7 0
2 years ago
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