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Lostsunrise [7]
4 years ago
10

Which is a polar molecule

Chemistry
2 answers:
tensa zangetsu [6.8K]4 years ago
6 0
Trifluoromethane is polar.  One side of this molecule is more positive than the other.
Hoochie [10]4 years ago
6 0

Answer:

c

Explanation:

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What ever your demcial is move it to the left twice until there is no demcial like 9.8 move twice 980
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How many moles of copper are present in a sample that contains 4.55 x 10^24 atoms of copper
FinnZ [79.3K]

Hope you could understand.

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3 0
2 years ago
Which of the following pairs of reactants will react together to produce water (H2O) as one of the products?
Rainbow [258]
1) <span>NaNO3 and H2O - no reaction , it is dissolution
2) no hydrogen to make water
3) </span><span>Fe(OH)3 (base) and H2SO4(acid)) 
base +acid ----> salt +water
4) </span><span>Li2O and Ba(OH)2
basic oxide and base ----> no reaction

so Answer number 3)
</span> 2Fe(OH)3 +3 H2SO4 ------>   Fe2(SO4)3 + 6H2O<span>

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7 0
3 years ago
Read 2 more answers
Calculate the number of moles of aluminum, sulfur, and oxygen atoms in 4.00 moles of aluminum sulfate, al2(so4)3. express the nu
bagirrra123 [75]
<span>To calculate the number of moles of aluminum, sulfur, and oxygen atoms in 4.00 moles of aluminum sulfate, al2(so4)3. We will simply inspect the "number" of aluminum, sulfur, and oxygen atoms available per one mole of the compound. Here we have Al2(SO4)3, which means that for every mole of aluminum sulfate, there are 2 moles of aluminum, 3 (1 times 3) moles of sulfur, and 12 (4x3) moles of oxygen. Since we have four moles of Al2(SO4)3 given, we simply multiply 4 times the moles present per 1 mole of the compound. So we have 4x2 = 8 moles of Al, 4x3 = 12 moles of sulfur, and 4x12 = 48 moles of oxygen.

So the answer is:
8,12,48


</span>
3 0
3 years ago
Read 2 more answers
A sample of gas initially has a volume of 2.25 L at 350 K and a pressure of 1.75 atm. What will be sample pressure if the volume
IRINA_888 [86]

Answer:

8.44 atm

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 2.25 L

Initial temperature (T₁) = 350 K

Initial pressure (P₁) = 1.75 atm

Final volume (V₂) = 1 L

Final temperature (T₂) = 750 K

Final pressure (P₂) =?

The final pressure of the gas can be obtained as illustrated below:

P₁V₁/T₁ = P₂V₂/T₂

1.75 × 2.25 / 350 = P₂ × 1 / 750

3.9375 / 350 = P₂ / 750

Cross multiply

350 × P₂ = 3.9375 × 750

350 × P₂ = 2953.125

Divide both side by 350

P₂ = 2953.125 / 350

P₂ = 8.44 atm

Thus, the final pressure of the gas is 8.44 atm.

7 0
3 years ago
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