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goldfiish [28.3K]
3 years ago
13

How does physical properties differ from chemical properties?

Chemistry
1 answer:
juin [17]3 years ago
4 0
It's A. 
Chemical properties cannot be determined by viewing or touching substance, and physical properties can be measured without changing the composition of matter:)
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Which properties can be measured without changing the chemical composition of the matter? _______ properties can be measured wit
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Answer:

\boxed {\sf Physical}

Explanation:

There are two main kinds of properties: chemical and physical.

Chemical properties, like the name suggests, have to be observed by changing the chemical composition.

That leaves <u>physical properties.</u> They can be measured without any chemical composition changes.

Some examples include: color, odor, mass, density, and volume. All can be measured with just the senses or measuring tools and no composition alterations are needed.

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The boiling point of water is a _____ property and is equal to _____.
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C. physical; 100°C

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What is the most important alloy that we use in construction?
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construction means everything is built from

EXCEPT NATURE

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If you have 100 ml of a 0.10 m tris buffer (pka 8.3) at ph 8.3 and you add 3.0 ml of 1.0 m hcl, what will be the new ph?
sukhopar [10]

The new pH is 7.69.

According to Hendersen Hasselbach equation;

The Henderson Hasselbalch equation is an approximate equation that shows the relationship between the pH or pOH of a solution and the pKa or pKb and the ratio of the concentrations of the dissociated chemical species. To calculate the pH of the buffer solution made by mixing salt and weak acid/base. It is used to calculate the pKa value. Prepare buffer solution of needed pH.

                       pH = pKa + log10 ([A–]/[HA])

Here, 100 mL  of  0.10 m TRIS buffer pH 8.3

                 pka = 8.3

         0.005 mol of TRIS.

∴  8.3 = 8.3 + log \frac{[0.005]}{[0.005]}

<em>    </em>inverse log 0 = \frac{[B]}{[A]}

   \frac{[B]}{[A]} = 1

Given; 3.0 ml of 1.0 m hcl.

           pka = 8.3

           0.003 mol of HCL.

pH = 8.3 + log \frac{[0.005-0.003]}{[0.005+0.003]}\\pH = 8.3 + log \frac{[0.002]}{[0.008]}\\\\pH = 8.3 + log {0.25}\\\\pH = 8.3 + (-0.62)\\pH = 7.69

Therefore, the new pH is 7.69.

Learn more about pH here:

brainly.com/question/24595796

#SPJ1

 

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