Answer:
Because the light only spears to part of the water so it would appear less deep
(a)
The formula is:
∑ F = Weight + T = mass * acceleration
as the elevator and lamp are moving downward, I choose downward forces to be
positive.
Weight is pulling down = +(9.8 * mass)
Tension is pulling up, so T = -63
Acceleration is upward = -1.7 m/s^2
(9.8 * mass) + -63 = mass * -1.7
Add +63 to both sides
Add (mass * 1.7) to both sides
(9.8 * mass) + (mass * 1.7) = 63
11.5 * mass = 63
mass = 63 / 11.5
Mass = 5.48 kg
(b)
Since the elevator and lamp are going upward, I choose upward forces to be
positive.
Weight is pulling down = -(9.8 * 5.48) = -53.70
Acceleration is upward, so acceleration = +1.7
-53.70 + T = 5.48 * 1.7
T = 53.70 + 9.316 = approx 63 N
The Tension is still the same - 63 N since the same mass, 5.48 kg, is being accelerated
upward at the same rate of 1.7 m/s^2
That's the answer: I've attached the pic
Answer:
1.35 m
Explanation:
Taking down to be positive, given:
Δx = Δy / tan 30.0º
v₀ₓ = 4.50 m/s
v₀ᵧ = 0 m/s
aₓ = 0 m/s²
aᵧ = 10 m/s²
Find: Δy
First, find the time it takes to land in terms of Δy.
Δy = v₀ t + ½ at²
Δy = (0 m/s) t + ½ (10 m/s) t²
Δy = 5t²
Next, find Δx in terms of t.
Δx = v₀ t + ½ at²
Δx = (4.50 m/s) t + ½ (0 m/s) t²
Δx = 4.50t
Substitute:
Δy = 5 (Δx / 4.50)²
20.25 Δy = 5 (Δx)²
4.05 Δy = (Δx)²
4.05 Δy = (Δy / tan 30.0º)²
4.05 Δy = 3 (Δy)²
1.35 = Δy
The basketball was thrown from an initial height of 1.35 m.
Graph: desmos.com/calculator/ujuzdo9xpr
