Pitch is the sensation of certain frequencies to the ear. High frequency = high pitch, low frequency = low pitch.
f = c(speed of the wave) / <span>λ (wavelength)
1. 343m/s / 0.77955m = 439.99 Hz
This corresponds to pitch A
2. 343m/s / 0.52028m = 659.26 Hz
</span> This corresponds to pitch E
<span>
3. 343m/s / 0.65552m = 523.349 Hz
</span>This corresponds to pitch C
4. using f = c / λ
λ = c / f<span>
= 343m/s / 587.33 = 0.583999 m = 0.584 m
</span>
Vt = Vboat - Vriver
Vt = 18 - 2.5 = 15.5 m/s
If the boat's direction is the same as the water, you sum the velocities of the river and the boat .
If you have no way to accurately measure all of the object's bumps and dimples, then the only way to measure its volume is by means of fluid displacement.
-- Put some water into a graduated (marked) container, read the amount of water, drop the object into the container, and read the new volume in the container. The volume of the object is the difference between the two readings.
-- Alternatively, stand an unmarked container in a large pan, and fill it to the brim. Slowly slowly lower the object into the unmarked container, while the pan catches the water that overflows from it. When the object is completely down in the container, carefully remove the container from the pan, and measure the volume of the water in the pan. It's equal to the volume of the object.
Answer:
Part a)
Part b)
Part c)
Part d)
from t = 0 to t = 4.9 s
so the reading of the scale will be same as that of weight of the block
Then its speed will reduce to zero in next 3.2 s
from t = 4.9 to t = 8.1 s
The reading of the scale will be less than the actual mass
Explanation:
Part a)
When elevator is ascending with constant speed then we will have
So it will read same as that of the mass
Part b)
When elevator is decending with constant speed then we will have
So it will read same as that of the mass
Part c)
When elevator is ascending with constant speed 39 m/s and acceleration 10 m/s/s then we will have
Reading is given as
Part d)
Here the speed of the elevator is constant initially
from t = 0 to t = 4.9 s
so the reading of the scale will be same as that of weight of the block
Then its speed will reduce to zero in next 3.2 s
from t = 4.9 to t = 8.1 s
The reading of the scale will be less than the actual mass
