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tiny-mole [99]
3 years ago
12

Which of the following does not use an internal combustion enginea. a cannonb. a lawnmowerc. a windmilld. a car

Physics
2 answers:
lara31 [8.8K]3 years ago
6 0
The windmill does not use a combustion engine.
damaskus [11]3 years ago
3 0

Answer:

c) a Windmill

Explanation:

A lawn mower may have a two stroke or a 4 stroke internal combustion engine.

Wind mill is a device that runs with wind. When wind blows, wings of the wind mill rotate. Wind mills are used to generate electricity. It is a renewable source of energy that requires large farms or open space for their establishment and maintenance.

In a cannon gun powder is ignited ,  not with the help of an engine , but a different method for its ignition.

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Why is it easier to open a door by holding it from it's edge​
Crazy boy [7]

Answer:

leverage

Explanation:

Leverage ...this allows you to use less force through a longer distance

3 0
2 years ago
What happens to the atomic number of an atom when the number of neutrons in the nucleus of that atom increases? a It decreases b
kupik [55]

Answer:

It remains the same

Explanation:

It remains the same. This is because the number of protons doesn't change and the number of protons determines the atomic number.

8 0
2 years ago
Action-reaction forces are not balanced forces because of what?
lara [203]

Oh but they are !

Newton's 3rd law of motion says that for every action, the <em><u>re</u></em>action is
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4 0
4 years ago
What shape is the JET experimental fusion reactor?
Sauron [17]

Answer:

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7 0
3 years ago
Read 2 more answers
A 41-turn square coil of area 0.074 m2 and a 123-turn circular coil are both placed perpendicular to the same changing magnetic
vesna_86 [32]

Answer:

<h3>The area of second coil is ≅ 0.025 m^{2}</h3>

Explanation:

Given :

No. of turns in the first coil N_{1} = 41

No. of turns in the second coil N_{2}  = 123

Area of first coil A_{1} = 0.074 m^{2}

According to the law of electromagnetic induction,

Induced emf = -N \frac{d \phi}{dt}

Where \phi = magnetic flux.

Since given in question emf of both coil is same so we compare above equation.

    -\frac{N_{1} d\phi _{1}   }{dt_{1} }  = -\frac{N_{2} d\phi _{2}   }{dt_{2} }

   \frac{N_{1} A_{1}   dB_{1}  }{dt_{1} }  = \frac{N_{2} A_{2} dB_{2}     }{dt_{2} }

        A_{2} = \frac{N_{1} A_{1}  }{N _{2}  }

        A_{2} = \frac{41 \times 0.074 }{123  }

        A_{2} = 0.0246 = 0.025 m^{2}

Therefore, the area of second coil is ≅ 0.025 m^{2}

4 0
4 years ago
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