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IgorC [24]
1 year ago
7

In a series rlc ac circuit, a second resistor is connected in parallel with the resistor previously in the circuit. as a result

of this change, what happens to the impedance of the circuit?
Physics
1 answer:
raketka [301]1 year ago
6 0

According to the given statement:

  • The frequency response does not change, which is the first thing we notice.
  • The new resistance at the resonance point causes a reduction in the circuit's current flow.
  •    Z = R + R₂
<h3>The definition of series circuits:</h3>

electrical circuit. The path that the entire current takes as it passes through each component makes up a series circuit. Branching is used in parallel circuits to divide the current and limit the amount that flows through each branch.

<h3>How does a series circuit operate?</h3>

According to this definition, there are three principles of series circuits: all parts share the same current, resistances add up to a larger total resistance, and voltage drops add up to a larger total voltage. In the definition of a series circuit, all of these guidelines have their origin.

<h3>According to the given information:</h3>

The impedance of a series circuit is

       Z₀² = R² + (X_L-X_C) ²

The initial resistance impedance shifts to when we add another resistor to the series

              Z² = (R + R₂) ² + (X_L - X_C) ²

Let's examine this sentence.

  • The frequency response remains unchanged, which is the first thing we notice.
  • The new resistance at the resonance point causes the circuit's current to decrease.

           Z = R + R₂

To know more about electrical circuit visit:

brainly.com/question/1922668

#SPJ4

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It takes 52,000 Joules to heat a cup of coffee to boiling from room temperature. How long a piece of 20 cm wide Aluminum foil wo
vovikov84 [41]

Answer:

L = 1.11 x 10^{6} m, is the length of piece of 20 cm wide Aluminum foil to make capacitor large enough to hold 52000 J of energy.

Explanation:

Solution:

Data Given:

Heat Energy = 52000 J

Dielectric Constant of the plastic Bag = 3.7 = K

Thickness = 2.6 x 10^{5} m =d

V = 610 volts

A = width x Length

width = 20 cm = 20 x 10^{-2} m

Length = ?

So,

we know that,

U = 1/2 C Δv^{2}

U = 52000 J

C = ?

V = 610 volts'

So,

U = 1/2 C Δv^{2}  

52000 J = (0.5) x (C) x (610^{2})

C = 0.28 F

And we also know that,

C = \frac{K*E*A}{d}

E = 8.85 x 10 ^{-12}

K = 3.7

A = 0.20 x L

d = 2.6 x 10^{5} m

Plugging in the values into the formula, we get:

0.28 = \frac{3.7 * 8.85 .10^{-12} * (0.20 . L) }{2.6 . 10^{5} }

Solving for L, we get:

L = 1.11 x 10^{6} m,

is the length of piece of 20 cm wide Aluminum foil to make capacitor large enough to hold 52000 J of energy.  

7 0
3 years ago
What is the accletation of a 1500kg with a net force of 7500 N
matrenka [14]
Acceleration formulae is:
a=Fnet/mass
According to the question
a=7500N/1500kg
a=5m/s sq.
3 0
3 years ago
A truck tire rotates at an initial angular speed of 21.5 rad/s. The driver steadily accelerates, and after 3.50 s the tire's ang
erma4kov [3.2K]

Given:

initial angular speed, \omega _{i} = 21.5 rad/s

final angular speed, \omega _{f} = 28.0 rad/s

time, t = 3.50 s

Solution:

Angular acceleration can be defined as the time rate of change of angular velocity and is given by:

\alpha = \frac{\omega_{f} - \omega _{i}}{t}

Now, putting the given values in the above formula:

\alpha = \frac{28.0 - 21.5}{3.50}

\alpha = 1.86 m/s^{2}

Therefore, angular acceleration is:

\alpha = 1.86 m/s^{2}

5 0
2 years ago
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