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IgorC [24]
1 year ago
7

In a series rlc ac circuit, a second resistor is connected in parallel with the resistor previously in the circuit. as a result

of this change, what happens to the impedance of the circuit?
Physics
1 answer:
raketka [301]1 year ago
6 0

According to the given statement:

  • The frequency response does not change, which is the first thing we notice.
  • The new resistance at the resonance point causes a reduction in the circuit's current flow.
  •    Z = R + R₂
<h3>The definition of series circuits:</h3>

electrical circuit. The path that the entire current takes as it passes through each component makes up a series circuit. Branching is used in parallel circuits to divide the current and limit the amount that flows through each branch.

<h3>How does a series circuit operate?</h3>

According to this definition, there are three principles of series circuits: all parts share the same current, resistances add up to a larger total resistance, and voltage drops add up to a larger total voltage. In the definition of a series circuit, all of these guidelines have their origin.

<h3>According to the given information:</h3>

The impedance of a series circuit is

       Z₀² = R² + (X_L-X_C) ²

The initial resistance impedance shifts to when we add another resistor to the series

              Z² = (R + R₂) ² + (X_L - X_C) ²

Let's examine this sentence.

  • The frequency response remains unchanged, which is the first thing we notice.
  • The new resistance at the resonance point causes the circuit's current to decrease.

           Z = R + R₂

To know more about electrical circuit visit:

brainly.com/question/1922668

#SPJ4

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