Answer:
a. 0.5307 sec
b. 0.4458 m
c. =
Explanation:
Horizontal Motion
It describes the dynamics of an object thrown horizontally in free air. The initial horizontal velocity is maintained all the time since no horizontal forces are acting. The initial vertical velocity is zero at launch time, but it grows downwards powered by the acceleration of gravity.
The object hits the ground at a distance x from the point of launching, after having traveled a vertical distance , taking a time t to complete the travel. The formulas who relate the different magnitudes are
The horizontal velocity is the same regardless of the elapsed time
The plate of apple pie left the counter at a speed
The counter is high.
a.
Knowing that
We use this formula to compute t
At the moment when the plate hits the floor y=0
Solving for t
b.
c.
d = distance the bowling ball has fallen = ?
g = acceleration due to gravity acting on the ball by earth = 9.8 m/s²
t = time of fall for the ball = 3.0 s
distance the ball has fallen is given as
d = (0.5) g t²
inserting the above values in the equation above
d = (0.5) (9.8 m/s²) (3.0 s)²
d = (0.5) (9.8 m/s²) (9.0 s²)
d = (4.9 m/s²) (9.0 s²)
d = 44.1 m
hence the distance fallen by the ball comes out to be 44.1 m
Conductivity would be the property.
Answer:
A. Force on parent is greater than the force on child
B. The net force acting on the bodies is zero for each.
C. the drag force on the parent is greater than the drag force on the child.
Explanation:
The child and the parent jump together form a certain height where the mass of the parent is greater than the mass of the child.
A
Before opening the parachute the drag force is negligible and so their velocity and acceleration are same simultaneously. The total force acting on the child is lesser than the total force of gravity on the child because the force of gravity is given as:
where:
m= mass
g= acceleration due to gravity
So when the mass is greater then the force of gravity is also greater on the body.
B
During the uniform velocity motion there is no acceleration in the body and hence we can say the there is no net force acting on the body.
The net force acting on the body is zero.
C
The force of drag acts due to parachute on each of the body when falling with uniform motion, this drag force is equal to the force of gravity acting on each of them individually.
So the drag force on the heavier body is greater than the drag force on the lighter body. During this condition the bodies fall with a uniform velocity called terminal velocity.
where:
density of the air
A= area normal to the direction of fall
v= terminal velocity
coefficient of drag
Answer:
The velocity of the skateboard is 0.774 m/s.
Explanation:
Given that,
The spring constant of the spring, k = 3086 N/m
The spring is stretched 18 cm or 0.18 m
Mass of the student, m = 100 kg
Potential energy of the spring,
To find,
The velocity of the car.
Solution,
It is a case of conservation of energy. The total energy of the system remains conserved. So,
v = 0.774 m/s
So, the velocity of the skateboard is 0.774 m/s.