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3 years ago

Which planet is the most massive? A.Jupiter B.Mercury C.Venus D.Neptune

Chemistry

2 answers:

Ainat [17]3 years ago

7 0

Jupiter is the biggest planet in are solar system

Svetradugi [14.3K]3 years ago

3 0

A) Jupiter

Jupiter is the largest planet in our solar system.

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I need help please WOTH this

barxatty [35]

Answer:

Kenma I'll help you! it's B.

Explanation:

I hope I helped you Kenma

7 0

2 years ago

On the reaction below, label the BSA, BSB, CA, and CB. CH3COOH + H2O → CH3COO– + H3O+

Ostrovityanka [42]

Answer:

Acid(BSA) = CH₃COOH

Base (BSB) = H₂O

Conjugate base (CB) = CH₃COO⁻

Conjugate acid (CA) = H₃O⁺

Explanation:

Equation of reaction;

CH₃COOH + H₂O → CH₃COO⁻ + H₃O⁺

Hello,

From my understanding of the question, we are required to identify the

1) Acid

2) Base

3) conjugate acid

4) conjugate base in the reaction

Acid (BSA) = CH₃COOH

Base (BSB) = H₂O

CA = conjugate acid = H₃O⁺

CB = conjugate base = CH₃COO⁻

7 0

2 years ago

How would you know if this combination is likely to be found in dirt? Please explain!

Elan Coil [88]

No it is not likely. That is a ratio of 10:4 N^14 and N^15 which doesn’t work. It needs a higher amount

4 0

2 years ago

Read 2 more answers

Physical changes occur when matter changes its property but not its

NNADVOKAT [17]

This statement is true

8 0

2 years ago

You need to prepare 100.0 mL of a pH 4.00 buffer solution using 0.100 M benzoic acid (p K a = 4.20 ) and 0.200 M sodium benzoate

bekas [8.4K]

Answer : The volume of sodium benzoate and benzoic acid solution mixed to prepare this buffer should be, 29.0 mL and 71 mL respectively.

Explanation :

Let the volume of sodium benzoate (salt) be, x

So, the volume of benzoic acid (acid) will be, (100 - x)

Using Henderson Hesselbach equation :

$pH=pK_a+\log \frac{[Salt]}{[Acid]}$

Now put all the given values in this expression, we get:

$4.00=4.20+\log \left(\frac{(\frac{0.200x}{100})}{(\frac{0.100(100-x)}{100})}\right)$

x = 29.0

The volume of sodium benzoate = x = 29.0 mL

The volume of benzoic acid (acid) = (100 - x) = (100 - 29.0) = 71 mL

Thus, the volume of sodium benzoate and benzoic acid solution mixed to prepare this buffer should be, 29.0 mL and 71 mL respectively.

5 0

2 years ago