Question

a wire carries 15 A. You form it into a singleturn circular loop with magnetic field 80 µT at the loop center. What is the loop radius?

Answer 1

Answer:

Radius of the loop, r = 0.12 m

Explanation:

It is given that,

Current flowing in the wire, I = 15 A

Magnetic field at the center of the loop, B = 80 μT = 80 × 10⁻⁶ T

The magnetic field at the center of the circular loop is given by :

$B=\dfrac{\mu_0I}{2r}$

R is the radius of loop

$r=\dfrac{\mu_oI}{2B}$

$r=\dfrac{4\times 3.14\times 10^{-7}\times 15}{2\times 80\times 10^{-6}}$

r = 0.12 m

So, the radius of the loop is 0.12 m

Hence, this is the required solution.

Answer 2

Use the formula B(at the center)= (4 pi * 10^(-7) ) * I (current)   / ( 2 radius)
and you will get the answer that will be 6.