a wire carries 15 A. You form it into a singleturn circular loop with magnetic field 80 µT at the loop center. What is the loop
2 answers:
Answer:
Radius of the loop, r = 0.12 m
Explanation:
It is given that,
Current flowing in the wire, I = 15 A
Magnetic field at the center of the loop, B = 80 μT = 80 × 10⁻⁶ T
The magnetic field at the center of the circular loop is given by :
R is the radius of loop
r = 0.12 m
So, the radius of the loop is 0.12 m
Hence, this is the required solution.
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Answer:
F=248.5W N
Explanation:
Newton's 2nd Law tells us that F=ma. We will use their averages always. The average acceleration the tennis ball experimented is, by definition:
Since we start counting at 0s and the ball departs from rest, this is just
So we can write:
Where in the last step we have just multiplied and divided by g, the acceleration of gravity. This allows us to introduce the weight of the ball W since W=gm, so we have:
Substituting our values:
Where the average force exerted has been written it terms of the tennis ball's weight W.
Answer:
84.6 J
Explanation:
The work done by the force is given by
where
W is the work done
F = 15 N is the force applied
d = 6.0 m is the displacement
is the angle between the force's direction and the displacement
Substituting the numbers into the equation, we find