Answer:
<h3>law</h3>
Explanation:
The law of conservation of energy states that the total amount of energy in a system remains constant.
Answer:
12900 W
24200 W
Explanation:
Given:
v₀ = 0 m/s
v = 1.3 m/s
t = 2.0 s
Find: a and Δx
v = at + v₀
(1.3 m/s) = a (2.0 s) + (0 m/s)
a = 0.65 m/s²
Δx = ½ (v + v₀) t
Δx = ½ (1.3 m/s + 0 m/s) (2.0 s)
Δx = 1.3 m
While accelerating:
Newton's second law:
∑F = ma
F − mg = ma
F = m (g + a)
F = (1500 kg + 400 kg) (9.8 m/s² + 0.65 m/s²)
F = 19855 N
Power = work / time
P = W / t
P = Fd / t
P = (19855 N) (1.3 m) / (2.0 s)
P ≈ 12900 W
At constant speed:
Newton's second law:
∑F = ma
F − mg = 0
F = mg
F = (1500 kg + 400 kg) (9.8 m/s²)
F = 18620 N
Power = work / time
P = W / t
P = Fd / t
P = Fv
P = (18620 N) (1.3 m/s)
P ≈ 24200 W
Answer:
The size of an object is directly proportional to the gravity
Explanation:
The size of an object has significant impact on the gravity exerted by such a body.
The more massive a body is, the larger the gravity it exerts.
The reason for this is because of the newton's law of universal gravitation.
- It states that "the gravitational force between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distances between them".
- As such, gravity is directly proportional to mass
1) Call F1 the larger force and F1x and F1y its its x-and-y- components.respectively.
I will use the complementary angle: 90 - 25 = 65 to work with the normal convention.
=> cos(65) = F1x / F1 => F1x = - F1*cos(65) (I choose negative as the west direction)
=> sin(65) = F1y / F1 => F1y = F1*sin(65) (I choose positive the north direction)
2) Call F2 the shorter force and F2x and F2y its components
=> cos(x) = F2x / F2 => F2x = F2*cos(x)
=> sin(x) = F2y / F2=> F2y = F2*sin(x)
3) You know that:
- F1 = 2F2
- The net force in the y direction is 430 N
- The net force in the x direction is 0
a) F1x + F2x = 0
=> -F1*cos(65) + F2*sin(x) = 0
=> F1*cos(65) = F2 sin(x) => sin(x) = [F1/F2] cos(65)
Remember F1 = 2F2 => F1/F2 = 2 => sin(x) = 2 cos(65) = 0.84524
=> x = arcsin(0.84524) = 57.7
b) F1y + F2y = 430 =>
F1 sin(65) + F2*sin(57.7) = 430 =>
0.9060F1 + 0.84524F2 430
F1 = 2F2 => 0.9060*2F2 + 0.84524F2 = 430 => 1.7512F2 = 430
=> F2 = 430 / 1.7512 = 245.54 N
=> F1 = 2*245.54 =491.1N
There you have the two forces.
The angle of the shorter force is 57.7 measured from the east to the north (this is north of east), which would be 90 - 57.7 = 32.3 degrees east of north..
Then the shorter force is 245.5 N at 32.3 degrees east of north
And the larger force is 491.1 N at 25.0 degrees west of north.
